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Ivanshal [37]
3 years ago
7

A company car is valued at $28,000 and will depreciate by

Mathematics
1 answer:
Ad libitum [116K]3 years ago
3 0

Answer:

14 years

Step-by-step explanation:

If the value of the car is $28,000 and each year the value goes down by $2,000 it will be $0 in 14 years. 28/2=14

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Ava's mom purchased a savings bond for Ava. The value of the savings bond increases by 3% each year. One year after it was purch
malfutka [58]

Answer:

Original Value= $361.21

Step-by-step explanation:

Giving the following information:

The value of the savings bond increases by 3% each year. One year after it was purchased, the value of the savings bond was $515.

<u>To calculate the original value of the bond, we need to use the following formula:</u>

OV= PV/(1+i)^n

OV= original value

PV= present value

i= increase rate

n= number of months

OV= 515 / (1,03^12)

OV= $361.21

5 0
3 years ago
What is the polynomial function if the zeros are -2,3,-4
navik [9.2K]
For the above equation and given zeros of polynomial equation we have;

y=(x+2)(x-3)(x+4)
y=(x^2+2x-3x-6)(x+4)
y=(x^2-x-6)(x+4)
y=(x^3-x^2-6x+4x^2-4x-24)
y=x^3+3x^2-10x-24
Therefore our answer is 3

Hope this helps. Any questions please just ask. Thank you.
3 0
4 years ago
Write 345,000 in scientific notation
mars1129 [50]
3.45x10^5 is the answer
7 0
4 years ago
Read 2 more answers
ASAP HELP ME!! PLEASE SHOW WORK AND CORRECT Answers!!! (JUST THE 1st ONE! And the answer I circled is wrong)
kumpel [21]
The awnser is 96 because you would chose the one bigger or you wouldn't chose the one smaller so choose a medium number 96
6 0
3 years ago
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I need help with #39-42, please explain.
shusha [124]

For question 39 & 40, we need to use the below equation to complete the sentence

l=m\sqrt{n}

Question 39:

When ' n ' increase, the \sqrt{n} will also increase and that multiplied with constant ' m ', the l will also increase.

Solution for question 39:

As n increases and m stays constant , l <u>increases</u>

-------

Question 40:

Solving the equation for m, we get

l = m\sqrt{n} \\ \\ m=\frac{l}{\sqrt{n}}

When ' l ' increases, the numerator increase, the denominator stays constant because 'n' stays constant, for this condition, the fraction increases.

Solution for question 40:

As l increase and n stays constant, m <em><u>increases</u></em>

------

For question 41 & 42, we need to use the below equation to complete the sentence

r=s^2/t^2

Question 41:

When s is triped, the equation will be...

r=(3s)^2/t^2=\frac{3^{2}s^{2}}{t^2}   =9s^2/t^2

Solution for question 41:

If s is tripled and t stays constant, r is multiplied by <em><u>9</u></em>

--------

Question 42:

When t is doubled, the equation will be...

r=s^2/(2t)^2=\frac{s^2}{2^2 \cdot t^2}=\frac{s^2}{4t^2}\\   \\ r=0.25s^2/t^2 \; \; (or) \; \; \frac{1}{4} \cdot \frac{s^2}{t^2}

Solution for 42:

If t doubled and s stays constant, r is multiplied by <em><u>1/4 or 0.25</u></em>


3 0
3 years ago
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