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juin [17]
3 years ago
5

When is the mean most useful in describing a set of data?

Mathematics
2 answers:
melamori03 [73]3 years ago
4 0
The range is wide is the correct answer
sergey [27]3 years ago
4 0
There is a outlier wen one point is far off from the rest of the points
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Luis does chores at home to earn extra money. Each week he earns $20. He already has $320 in his savings account, and is trying
Setler [38]

Answer:

30.5 Weeks

Step-by-step explanation:

The phone costs $930, and he already has $320 saved in his bank account so subtract 320 from 930. You will get 610. Then, you take 610 and divide it by 20 because he earns $20 a week. I hope this helped.

8 0
3 years ago
Solve for all values of x (x+9)2=4
serg [7]

Answer:

x = -7

Step-by-step explanation:

you have to distribute the 2 to what is in the parenthesis, then you get left with 2x+18=4 so subtract the 18 from both sides leaving you with 2x=-14 so you divide both by 2 leaving you with x=-7.

7 0
3 years ago
Read 2 more answers
What is the area of an isosceles trapezoid, if its shorter base has length of 18 cm, the length of the altitude is 9 cm, and the
padilas [110]

The formula for the area of a triangle of base b and altitude h is A = (1/2)(b)(h).

Here, b = 18 cm and h = 9 cm.  Thus, the desired area is:

        (18 cm)(9 cm)

A = ----------------------- = 81 cm^2

                  2

This problem gives you more info than is needed to solve it.  The area of the given triangle is 81 cm^2.

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=9%5C%3A%20%20%5C%3A%20%20%5Cfrac%7B%20%5Csin%28%20%5Ctheta%29%20%7D%7B1%20%2B%20%20%5Ccos%28%2
PIT_PIT [208]

Option (b) is your correct answer.

Step-by-step explanation:

\large\underline{\sf{Solution-}}

Given Trigonometric expression is

\rm :\longmapsto\:\dfrac{sin\theta }{1 + cos\theta }

So, on rationalizing the denominator, we get

\rm \:  =  \: \dfrac{sin\theta }{1 + cos\theta }  \times \dfrac{1 - cos\theta }{1 - cos\theta }

We know,

\purple{\rm :\longmapsto\:\boxed{\tt{ (x + y)(x - y) =  {x}^{2} -  {y}^{2} \: }}}

So, using this, we get

\rm \:  =  \: \dfrac{sin\theta (1  -  cos\theta )}{1 -  {cos}^{2}\theta  }

We know,

\purple{\rm :\longmapsto\:\boxed{\tt{  {sin}^{2}x +  {cos}^{2}x = 1}}}

So, using this identity, we get

\rm \:  =  \: \dfrac{sin\theta (1 -  cos\theta )}{{sin}^{2}\theta  }

\rm \:  =  \: \dfrac{1 - cos\theta }{sin\theta }

<u>Hence, </u>

\\ \red{\rm\implies \:\boxed{\tt{ \rm \:\dfrac{sin\theta }{1 + cos\theta }   =  \: \dfrac{1 - cos\theta }{sin\theta } }}} \\

3 0
2 years ago
Read 2 more answers
Look at the rectangle and the square:
Rudiy27

Answer:

bla bla bla bla bla bla

6 0
3 years ago
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