So.. hmm notice the picture below
r = h, due to similar triangles ratio, whatever "h" may be
now, we're given how much water is being poured into the cup per sec
namely dv/dt the volume's rate
so.. hmmm
Answer:
15.0
Step-by-step explanation:
answer attached
hope this helps!
Step-by-step explanation:
(7,16) (3,8)
(8-16)/(3-7)
-8/-4= 2
y - 16 = 2(x - 7)
y - 16 = 2x - 14
y = 2x + 2
Answer:
answer is A
Step-by-step explanation:
Answer:
![p=28.2\:\text{units},\\A=40.2\:\text{square units}}](https://tex.z-dn.net/?f=p%3D28.2%5C%3A%5Ctext%7Bunits%7D%2C%5C%5CA%3D40.2%5C%3A%5Ctext%7Bsquare%20units%7D%7D)
Step-by-step explanation:
The irregular shape's area consists of the sum of the areas of all the shapes that make it up.
Area of pink triangle: ![\frac{1}{2}\cdot 3 \cdot 3=4.5](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Ccdot%203%20%5Ccdot%203%3D4.5)
Area of purple square: ![3^2=9](https://tex.z-dn.net/?f=3%5E2%3D9)
Area of green quadrilateral: ![3\cdot 2.9=8.7](https://tex.z-dn.net/?f=3%5Ccdot%202.9%3D8.7)
Area of blue triangle: ![\sqrt{10.25(10.25-8.5)(10.25-6)(10.25-6)}=17.99989](https://tex.z-dn.net/?f=%5Csqrt%7B10.25%2810.25-8.5%29%2810.25-6%29%2810.25-6%29%7D%3D17.99989)
Therefore, the area of the irregular polygon is
.
The perimeter of the irregular polygon consists of certain shred sides from the four polygons that make up:
![p=3+3+3+4.2+3+6+6=\boxed{28.2\:\text{units}}](https://tex.z-dn.net/?f=p%3D3%2B3%2B3%2B4.2%2B3%2B6%2B6%3D%5Cboxed%7B28.2%5C%3A%5Ctext%7Bunits%7D%7D)