For the first question, you need to count all of your choices. Kepp in mind, it will be a fraction. Then count all of your "V6".
12/24 = 1/2
Hope this helps!!
Answer:
0.2575
<em>That’s your answer! </em>:)
Answer:
The confidence interval is from 69.82 o 82.18
Step-by-step explanation:
Using this formula X ± Z (s/√n)
Where
X = 76 --------------------------Mean
S = Standard Deviation
If Variance = 144
S = √144
S = 12
n = 25 ----------------------------------Number of observation
Z = 2.576 ------------------------------The chosen Z-value from the confidence table below
Confidence Interval || Z
80%. || 1.282
85% || 1.440
90%. || 1.645
95%. || 1.960
99%. || 2.576
99.5%. || 2.807
99.9%. || 3.291
Substituting these values in the formula
Confidence Interval (CI) = 76 ± 2.576 (12/√25)
CI = 76 ± 2.576(12/5)
CI = 76 ± 2.576(2.4)
CI = 76 ± 6.1824
CI = 76 + 6.1824 ~ 76 - 6.1824
CI = 82.1824 ~ 69.8176
CI = 82.18 ~ 69.82
In other words the confidence interval is from 69.8176 to 82.1824
<h3>
Answer: D) infinitely many solutions</h3>
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Explanation:
Let's solve the first equation for y
4x - 2y = 6
4x-6 = 2y
2y = 4x-6
y = (4x-6)/2
y = (4x/2) - (6/2)
y = 2x - 3
After doing so, we see that 4x-2y = 6 is equivalent to y = 2x-3
Therefore, the original system of equations is effectively listing the same equation twice (one has a different form compared to the other).
Both equations in this system produce the same graph, which leads to infinitely many solutions. All solutions are on the line y = 2x-3.
You can say that all solutions are in the form (x, 2x-3) where x is any real number you want.
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Here's another approach using substitution
4x - 2y = 6 ... start with the first equation
4x - 2( y ) = 6
4x - 2( 2x-3 ) = 6 .... replace y with 2x-3; ie plug in y = 2x-3
4x - 2(2x) - 2(-3) = 6
4x - 4x + 6 = 6
0x + 6 = 6
0 + 6 = 6
6 = 6
We get a true statement. The last equation is always true regardless of what we plug in for x, so this is another way to see how we get to infinitely many solutions.
Side note: the system is considered dependent since one equation depends on the other. The system is also consistent since it has at least one solution.
