One number: x
Its consecutive: x + 1
Product:
x(x+1)=121
x² + x - 121 = 0
Δ = 1² - 4.1.(-121)
Δ = 1+484
Δ = 485
As square root of 485 is not integer, do not exist two consecutive numbers with product of 121
Answer:
The commutive property used twice, once on each of the two multiplication
The commutive property is where you can be able to switch around the numbers to multiply the problem to get your solution.
If you times it the answer is going to be 1,200
If a:b=c:d then a/b=c/d and ad=bc
so
if 16:14=64:60 then 16/14=64/60 and (16)(60)=(14)(64)
(16)(60)=960
(14)(64)=896
960≠896
not equivilent
the easiest way is to simplify them
16/14=8/7
64/60=32/30=16/15
not equal
not equivilent
