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Basile [38]
3 years ago
5

What equation fits the table

Mathematics
2 answers:
KatRina [158]3 years ago
8 0
I’m pretty sure the answer is c
Rufina [12.5K]3 years ago
3 0
C. y=3x because every x value when multiplied by three results in the answer of y
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HELP ASAP!!!!
Assoli18 [71]

Answer:

% error = 3.3%

Step-by-step explanation:

Percent Error Formula:

% error = ( (MeasuredValue - AcceptedValue) / AcceptedValue ) * 100

% error = ( (12.7 - 12.3) / 12.3 ) * 100

% error =  (0.4/12.3) * 100

% error = (0.03252033) * 100

% error = 3.25203252

% error = 3.3%

5 0
3 years ago
The space shuttle travels at 28,000 km per hour. Using that information, estimate how many hours it will take the shuttle to rea
spayn [35]

Subtract the distance of the Earth from the sun from the distance of Saturn from the sun to find the distance from Earth to Saturn:

1,424,000,000 - 149,600,000 = 1,274,400,000 km ( Saturn from Earth)

Divide the distance by the speed to find the time:

1,274,400,000 km / 28,000 km per hour = 45,514.2857 hours.

Round to 45,514 hours.

3 0
3 years ago
What is 3(x+3)=2(x12) can u help me
Soloha48 [4]
You didn't type the equation correctly. 
3 0
3 years ago
Use a half-angle identity to find the exact value
Tatiana [17]

Given:

\cos 15^{\circ}

To find:

The exact value of cos 15°.

Solution:

$\cos 15^{\circ}=\cos\frac{ 30^{\circ}}{2}

Using half-angle identity:

$\cos \left(\frac{x}{2}\right)=\sqrt{\frac{1+\cos (x)}{2}}

$\cos \frac{30^{\circ}}{2}=\sqrt{\frac{1+\cos \left(30^{\circ}\right)}{2}}

Using the trigonometric identity: \cos \left(30^{\circ}\right)=\frac{\sqrt{3}}{2}

            $=\sqrt{\frac{1+\frac{\sqrt{3}}{2}}{2}}

Let us first solve the fraction in the numerator.

            $=\sqrt{\frac{\frac{2+\sqrt{3}}{2}}{2}}

Using fraction rule: \frac{\frac{a}{b} }{c}=\frac{a}{b \cdot c}

            $=\sqrt{\frac {2+\sqrt{3}}{4}}

Apply radical rule: \sqrt[n]{\frac{a}{b}}=\frac{\sqrt[n]{a}}{\sqrt[n]{b}}

           $=\frac{\sqrt{2+\sqrt{3}}}{\sqrt{4}}

Using \sqrt{4} =2:

           $=\frac{\sqrt{2+\sqrt{3}}}{2}

$\cos 15^\circ=\frac{\sqrt{2+\sqrt{3}}}{2}

5 0
3 years ago
Question 2 of 10
UNO [17]

Answer:

9800000

Step-by-step explanation:

8 0
2 years ago
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