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drek231 [11]
3 years ago
9

For which values of K with the product of K / 3 12 be greater than 12

Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
7 0

Answer:

The values of k are all real numbers greater than 3

Step-by-step explanation:

we have

(\frac{k}{3})12 > 12

Solve for k

Divide 12 by 3

4k > 12

Divide by 4 both sides

4k/4 > 12/4

k > 3

The solution is the interval ------> (3,∞)

All real numbers greater than 3

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I NEED HELP WITH THESE TWO QUESTIONS PLZ DO NOT ANSWER IF YOU CANNOT EXPLAIN THE ANSWER
Murljashka [212]

9514 1404 393

Answer:

  1. asymptotes: x=-6, x=6, y=0; zero: x=0

  2. 20 blue fish

Step-by-step explanation:

1. The vertical asymptotes are where the denominator is zero. It factors as (x-6)(x+6), so will have zeros at x=-6 and x=6.

The horizontal asymptote is at the limit when x goes to infinity. Here, the ratio of highest-degree terms is 6/x, so the value goes to zero as x gets large.

The zero is where the numerator is zero, at x=0.

In summary:

  • vertical asymptotes: x = ±6
  • horizontal asymptote: y = 0
  • zero: (0, 0)

__

2. 60% are red, so 40% are blue. The difference in percentages is 60%-40% = 20%. The percentage of blue fish (40%) is twice the difference (=2×20%), so the number of blue fish is twice the difference in numbers.

  blue fish = 2×10 = 20 fish

<em><u>Check</u></em>

There are then 20+10=30 red fish, so 20+30=50 fish total. Reds are 30/50 = 60% of the total.

<u><em>Additional comment</em></u>

I find it often works well to work with ratios, which I can often do in my head. Other folks like to see equations. Here, we could write equations like ...

  r = 60%(r + b) . . . . reds are 60% of the total

  r - b = 10 . . . . . . . . 10 more reds than blues

We want the value of b, so we can eliminate r by substituting for it:

  r = 10 + b . . . . from the second equation above

  (10 +b) = 0.60((10 +b) + b) . . . . substitute for r

  10 +b = 6 + 1.2b . . . simplify

  4 = 0.2b . . . . subtract b+6

  20 = b . . . . . . multiply by 5 (there are 20 blue fish)

6 0
3 years ago
I need some help on these 3 questions :)
wlad13 [49]

The factor of the polynomial, the area of the pool and the simplified expression are all algebraic expressions

<h3>How to simplify the expressions?</h3>

<u>Factor of the polynomial</u>

The polynomial is given as:

2x^3 + 6x^2 + 6x + 18

Factor out 2

2x^3 + 6x^2 + 6x + 18 = 2(x^3 + 3x^2 + 3x + 9)

Factorize

2x^3 + 6x^2 + 6x + 18 = 2(x^2(x + 3) + 3(x + 3))

Factor out x + 3

2x^3 + 6x^2 + 6x + 18 = 2(x^2 + 3)(x + 3)

Expand

2x^3 + 6x^2 + 6x + 18 = (2x^2 + 6)(x + 3)

Hence, 2x^2 + 6 is a factor of the polynomial 2x^3 + 6x^2 + 6x + 18

<u>The length of the pool</u>

The given parameters are:

Area = 2x^3 - 29x + 12

Width = x + 4

The length is calculated as:

Length = Area/Width

This gives

Length = 2x^2 - 29x + 12/x + 4

Factorize the numerator

Length = (2x^2 - 8x + 3)(x + 4)/x + 4

Cancel out x + 4

Length = 2x^2 - 8x + 3

Hence, the length of the pool is 2x^2 - 8x + 3

<u>Simplify the expression</u>

The expression is given as:

(3s^2 - 2s + 1) \div (s^2 - s + 2)

Evaluate the quotient

3 + (s - 5)/(s^2 - 5 + 2)

Hence, the simplified expression is 3 + (s - 5)/(s^2 - 5 + 2)

Read more about algebraic expressions at:

brainly.com/question/2164351

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