Answer: see below
<u>Step-by-step explanation:</u>
1) 10, 2, 1.2, 1.12, 1.112, 1.1112
t₁ = 10
t₂ = 10/10 + 1 = 2
t₃ = 2/10 + 1 = 1.2
t₄ = 1.2/10 + 1 = 1.12
t₅ = 1.12/10 + 1 = 1.112
t₆ = 1.112/10 + 1 = 1.1112
2) 10, 2, -2, -4, -5, -5.5, ...
t₁ = 10
t₂ = 10/2 - 3 = 2
t₃ = 2/2 - 3 = -2
t₄ = -2/2 - 3 = -4
t₅ = -4/2 - 3 = -5
t₆ = -5/2 - 3 = -5.5
Answer:
It can be concluded that the intersection of a chord and the radius that bisects it is at right angle. The two are perpendicular.
Step-by-step explanation:
i. Construct the required circle of any radius as given in the question, then locate the chord. A chord joins two points on the circumference of a circle, but not passing through its center.
ii. Construct the radius to bisect the chord, dividing it into two equal parts.
Then it would be observed that the intersection of a chord and the radius that bisects it is at right angle. Thus, the chord and radius are are perpendicular to each other.
The construction to the question is herewith attached to this answer for more clarifications.
