Answer:
sln
f(x) =-22+x+14 put 2 in x
f(2)=-22+2+14
f(2) =38
9514 1404 393
Answer:
- square: 12 ft sides
- octagon: 6 ft sides
Step-by-step explanation:
This problem can be worked in your head.
If the perimeters of the square and regular octagon are the same, the side length of the 4-sided square must be the same as the length of 2 sides of the 8-sided octagon. Since the side of the square is 6 ft more than the side of the octagon, each side of the octagon must be 6 ft, and each side of the square must be 12 ft.
__
We can let s represent the side length of the octagon. Then we have ...
8s = perimeter of octagon
4(s +6) = perimeter of square
These are equal, so ...
4(s +6) = 8s
s +6 = 2s . . . . . . divide by 4
6 = s . . . . . . . . . . subtract s
The octagon has 6-ft sides; the square has 12-ft sides.
Answer:
BRUH
Step-by-step explanation:
BRUH
The answer is B. Just multiply all of them then divide
Answer:
Lisa spends $138.40 on school lunches in 16 weeks.
Step-by-step explanation:
You have to multiply 8.65 by 16, since 8.65 is how much money Lisa spends each week for lunch, then you multiply by 16 since the problem calls for 16 weeks, then you get your final answer of $138.40.