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Vedmedyk [2.9K]
3 years ago
12

Wut answer to 2q×2q×2q×2q×2q

Mathematics
1 answer:
tankabanditka [31]3 years ago
6 0

Answer:

32q5

Step-by-step explanation:

2x2x2x2x2= 32 qxqxqxqxq=q5

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Answer:

I wont tell you the answer but I can tell you how to solve this one.

Step-by-step explanation:

If they are both squared then square them. Once you have the hypotenuse and the leg squared subtract the leg from the hypotenuse. That's your answer. Then you un- square it by finding the square root of the new number. That square root is your answer

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Solve for x.<br> Sqrt8 (Sqrt2 - x) = 11
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Answer:\frac{-7\sqrt{2} }{4}

Step-by-step explanation:

So first, let's get rid of the parentheses. We can multiply it out to get \sqrt{16}-x\sqrt{8} =11. We know that the square root of 16 is ±4, so now our equation is ±4 - x\sqrt{8}=11. I'm guessing since the problem only has one solution it's most likely only positive 4, so let's revise our equation to 4 - x\sqrt{8}=11. We can use inverse operations to make the a little easier to solve: -7= x\sqrt{8}. We divide both sides by \sqrt{8} to get \frac{-7}{\sqrt{8} } =x, which we can rationalize (remove the square root from the denominator so that it's a proper answer) by multiplying by \frac{\sqrt{8} }{\sqrt{8} } (which is equal to one so we can use it) which is equal to \frac{-7\sqrt{8} }{8}. Let's finish this by simplifying it. \sqrt{8} =2\sqrt{2} (2x2^{2}). We can simplify it further by simplifying the 2, making it \frac{-7\sqrt{2} }{4}.

Hope this wasn't too confusing! I'll answer any questions.

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3 years ago
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