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MA_775_DIABLO [31]
2 years ago
14

−4x−2 + 3y0 if x = 2 and y = 5

Mathematics
1 answer:
Kazeer [188]2 years ago
5 0

Hey there!

-4x^-2 + 3y^0

= -4(2)^-2 + 3(5)^0

= -4(1/4) + 3(5)^0

= -1 + 3(5^0)

= -1 + 3(1)

= -1 + 3

= 2

Therefore, the answer should be: 2

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

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Write the equation of a parabola having the vertex (1, −2) and containing the point (3, 6) in vertex form. Then, rewrite the equ
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PART A

The equation of the parabola in vertex form is given by the formula,

y - k = a {(x - h)}^{2}

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We substitute these values to obtain,


y  + 2 = a {(x - 1)}^{2}

The point, (3,6) lies on the parabola.

It must therefore satisfy its equation.


6  + 2 = a {(3 - 1)}^{2}


8= a {(2)}^{2}


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Hence the equation of the parabola in vertex form is


y  + 2 = 2 {(x - 1)}^{2}


PART B

To obtain the equation of the parabola in standard form, we expand the vertex form of the equation.

y  + 2 = 2{(x - 1)}^{2}

This implies that

y + 2 = 2(x - 1)(x - 1)


We expand to obtain,


y + 2 = 2( {x}^{2}  - 2x + 1)


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y + 2 = 2 {x}^{2}  - 4x + 2


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Answer:

Option B. A = (5/6)^-⅛

Step-by-step explanation:

From the question given above, we obtained:

(5/6)ˣ = A¯⁸ˣ

We can obtain the value of A as follow:

(5/6)ˣ = A¯⁸ˣ

Cancel x from both side

5/6 = A¯⁸

Recall:

M¯ⁿ = 1/Mⁿ

A¯⁸ = 1/A⁸

Thus,

5/6 = 1/A⁸

Cross multiply

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Divide both side by 5

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Take the 8th root of both sides

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Recall

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Recall:

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