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Ymorist [56]
3 years ago
10

What is the maximum number of turns for the graph of f(x)=x^4+3x^2?

Mathematics
1 answer:
Stels [109]3 years ago
6 0

Answer:

The turns of a graph is represented by the number of maximum or minimum that the function has.

If we differenciate f(x) we get:

f'(x)=4x^3+6x

f'(x)=2x(2x^2 + 3)

Therefore f'(x) =0, when x=0. Given that negative roots are not defined.

Therefore, the number of turns will be given by the number of solutions of f'(x) which is 1.

Attached you find the graph of the function which confirms the number of turns.

If the function had other solutions, the maximum number of turns it could have is 3! because f'(x) is a third degree polynomial, therefore it can't have more than 3 solutions!

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To find the surface area of a cube, use the formula: surface area = 6s^2, where s is the length of one of the sides. If you don't know the length of the sides, you can find the surface area using volume. Just find the cube root of the volume, which is equal to the length of one side of the cube.

Step-by-step explanation:

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36 in

Step-by-step explanation:

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3 years ago
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Step-by-step explanation:

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3 years ago
Gina shows the steps she took to find the solution of the inequality below.
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Answer:

hello,2 th made from the wrong place.

because She should have distributed the -2 inside the parentheses.

the process should be like this;

19-2(1-x)<13

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6 0
3 years ago
Suppose a triangle has two sides of length 42 and 35, and that the angle between these two sides is 120 degrees. What is the len
FrozenT [24]

Answer:

Option D

Step-by-step explanation:

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