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Darya [45]
2 years ago
9

Solve for x. −2(x+1/4)+1=5​

Mathematics
2 answers:
larisa [96]2 years ago
5 0

Answer: The answer to this is x= -9/4

muminat2 years ago
4 0

Answer:

\boxed {x = - \frac{9}{4}}

Step-by-step explanation:

Solve for the value of x :

-2(x + \frac{1}{4}) + 1 = 5

-Use Distributive Property:

-2(x + \frac{1}{4}) + 1 = 5

-2x + \frac{-2}{4} + 1 = 5

-Reduce the fraction \frac{-2}{4} to the lowest terms by canceling out 2 :

-2x + \frac{-2}{4} + 1 = 5

-2x - \frac{1}{2} + 1 = 5

- Convert the integer 1 to \frac{2}{2} :

-2x - \frac{1}{2} + 1 = 5

-2x - \frac{1}{2} + \frac{2}{2} = 5

-Since both fractions -\frac{1}{2} and \frac{2}{2} have the same denominator, you add the numerators together:

-2x - \frac{1}{2} + \frac{2}{2} = 5

-2x + \frac{1}{2} = 5

-Change the integer 5 to \frac{10}{2} and subtract \frac{1}{2} on both sides. Then, when both fractions have the same denominator, you subtract them, by subtracting the numerators:

-2x +  \frac{1}{2} -  \frac{1}{2} = \frac{10}{2}  -  \frac{1}{2}

-2x = \frac{9}{2}

-Divide by Multiplying 2 and -2 :

\frac{-2x}{-2} = \frac{9}{2 (-2)}

x = \frac{9}{-4}

-Rewrite the answer:

x = \frac{9}{-4}

\boxed {x = - \frac{9}{4}}

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1 + tanx / 1 + cotx =2
Lera25 [3.4K]

Answer:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or x = tan^(-1)(-(i sqrt(3))/2 + 1/2) + π n_2 for n_2 element Z

Step-by-step explanation:

Solve for x:

1 + cot(x) + tan(x) = 2

Multiply both sides of 1 + cot(x) + tan(x) = 2 by tan(x):

1 + tan(x) + tan^2(x) = 2 tan(x)

Subtract 2 tan(x) from both sides:

1 - tan(x) + tan^2(x) = 0

Subtract 1 from both sides:

tan^2(x) - tan(x) = -1

Add 1/4 to both sides:

1/4 - tan(x) + tan^2(x) = -3/4

Write the left hand side as a square:

(tan(x) - 1/2)^2 = -3/4

Take the square root of both sides:

tan(x) - 1/2 = (i sqrt(3))/2 or tan(x) - 1/2 = -(i sqrt(3))/2

Add 1/2 to both sides:

tan(x) = 1/2 + (i sqrt(3))/2 or tan(x) - 1/2 = -(i sqrt(3))/2

Take the inverse tangent of both sides:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or tan(x) - 1/2 = -(i sqrt(3))/2

Add 1/2 to both sides:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or tan(x) = 1/2 - (i sqrt(3))/2

Take the inverse tangent of both sides:

Answer:  x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or x = tan^(-1)(-(i sqrt(3))/2 + 1/2) + π n_2 for n_2 element Z

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Answer:

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Step-by-step explanation:

The equation is...

9.5x+105=14.75x

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