Answer:
3) (2,-9)
4) (0,-5)
5) (1,-8)
Step-by-step explanation:
3)
The vertex will occur between you x-intercepts.
You already found that happens at x=2.
To find the corresponding y-coordinate, replace x in
f(x)=(x+1)(x-5) with 2:
f(2)=(2+1)(2-5)
f(2)=(3)(-3)
f(2)=-9
So the vertex is (2,-9).
4)
The y-intercept is when x=0.
So in f(x)=(x+1)(x-5) replace x with 0:
f(0)=(0+1)(0-5)
f(0)=(1)(-5)
f(0)=-5
So the y-intercept is (0,-5).
5)
To find another point just plug in anything besides any x already used.
We preferably want to use a value of x that will keep us on their grid however far up,down,left, or right their grid goes out. So I'm going to choose something close to the vertex which is at x=2. Let's go with x=1.
So replace x in f(x)=(x+1)(x-5) with x=1:
f(1)=(1+1)(1-5)
f(1)=(2)(-4)
f(1)=-8
So another point to graph is (1,-8).
So first you have to do 18 multiply by 2/9. This gets you 4, next you multiply by 1/2. This gets you 2.
ANSWER: She will have 2 stamps left.
Ok so lets plug in a first -1/3(-3) would equal 9 a is the accurate answer
Answer:
StartFraction 6 Over 5 x Superscript 10 Baseline EndFraction
Step-by-step explanation:
Apparently you want to simplify ...
The applicable rules of exponents are ...
(a^b)(a^c) = a^(b+c)
1/a^b = a^-b
(a^b)^c = a^(bc)
__
So the expression simplifies as ...
.68
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