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notka56 [123]
3 years ago
15

I need help please????!

Mathematics
1 answer:
horsena [70]3 years ago
6 0
The answer to your question is the first option because 6*3 is 18
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If the perimeter of one face of a cube is 22.4 cm, determine, to the nearest hundredth, its lateral surface area. *
mr Goodwill [35]
22.4/4 = 5.6 cm

5.6^2 = 31.36 cm^2 per side

Since the later surface area only counts for 4/6 sides on the cube, (31.36)(4) = 125.44 cm^2
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3 years ago
What is the number equal to 5 tens and 13 ones
masya89 [10]
63 is what 5 tens and 13 ones equal
8 0
3 years ago
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Help me please!!!!!!!!!!​
weeeeeb [17]

Answer:

  • slope: -5/3
  • y-intercept: 2
  • x-intercept: 6/5 = 1.2

Step-by-step explanation:

Finding the slope is perhaps easiest done by solving for y.

  5x -6 = -3y . . . . subtract 3

  y = -5/3x +2 . . . divide by -3

This is slope-intercept form, so we can see both the slope (the coefficient of x, -5/3) and the y-intercept (the constant, +2).

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To find the x-intercept, we set y=0 and solve for x. This might be most easily done using the original equation:

  5x -3 = 0 +3 . . . . set y = 0

  5x = 6 . . . . . . . . . add 3 to get the x-term by itself

  x = 6/5 = 1.2 . . . . divide by the coefficient of x. This is the x-intercept.

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Slope = -5/3

y-intercept = 2

x-intercept = 6/5

3 0
3 years ago
If KJ = 33 and KN = <img src="https://tex.z-dn.net/?f=%206%5Csqrt%7B10%7D%20%20" id="TexFormula1" title=" 6\sqrt{10} " alt=" 6\
Simora [160]
KJ is the hypotenuse of the right triangle KJN, therefore:KJ^2 = KN^2 + JN^233^2 = (6sqrt10)^2 + JN^21089 = 360 + JN^2JN^2 = 729JN = 27
The figure is a trapezoid, since GH // JI, and MN is perpendicular to HI. Therefore GN = JN = 27. The length of GJ = 54.

7 0
3 years ago
5. (08.01) Line M is represented by the following equation: x + y = -1 What is most likely the equation for line P so the set of
vodka [1.7K]
You welcome brada


correct way 2 life =420

4 0
3 years ago
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