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Lesechka [4]
2 years ago
13

A horizontal line has points J, K, L. A line extends from point K up and to the right to point M. Angle J K M is (10 y + 6) degr

ees and angle M K L is (8 y minus 6) degrees
What is the value of y?
y =

Find the following angle measures.
mAngleJKM = °
mAngleMKL = °

Mathematics
2 answers:
Temka [501]2 years ago
8 0

Answer:

The found values are:

y = 10

<JKM = 106°

<MKL = 74°

Step-by-step explanation:

(See the diagram attached)

As JKL is a straight horizontal line, angle measure from JK to KL is 180°.

We can see in the diagram that line KM is dividing this angle of 180° into 2 unequal parts.

Which means that the sum of <JKM and <MKL is equals to 180°.

Mathematically, it can be written as:

Substitute the values of both angle to solve the equation:

(10y+6)+(8y-6) = 180\\18y=180\\y=\frac{180}{18}\\y=10

Put in the formulas of both angle to find their values:

<JKM = 10y + 6

<JKM = 10(10)+6

<JKM = 106°

<MKL = 8y - 6

<MKL = 8(10)-6

<MKL = 74°

frozen [14]2 years ago
5 0

Answer:

y = 10

<JKM = 106°

<MKL = 74°

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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icang [17]
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3 0
3 years ago
In ΔKLM, l = 48 inches, ∠K=55° and ∠L=46°. Find the length of k, to the nearest inch.\
s2008m [1.1K]

Given:

In  ΔKLM, l = 48 inches, ∠K=55° and ∠L=46°.

To find:

The length of k, to the nearest inch.

Solution:

According to Law of sine,

\dfrac{a}{\sin A}=\dfrac{b}{\sin B}=\dfrac{c}{\sin C}

In ΔKLM, using law of sine, we get

\dfrac{k}{\sin K}=\dfrac{l}{\sin L}

\dfrac{k}{\sin (55^\circ)}=\dfrac{48}{\sin (46^\circ)}

k=\dfrac{48\times \sin (55^\circ)}{\sin (46^\circ)}

On further simplification, we get

k=\dfrac{48\times 0.819152}{0.7193398}

k=\dfrac{39.319296}{0.7193398}

k=54.66025&#10;

Approximate the value to the nearest inch.

k\approx 55&#10;

Therefore, the length of k is 55 inch.

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