Let
e = Gibson Explorer’s = 20
v = Gibson Flying V’s
So, our problem is
<u>Maximize</u>Money = 80e + 5v<span>
<u>Subject to</u>0 </span>≤ <span>e ≤ 20
</span>0 ≤ v ≤ 20
0 ≤ e + v ≤ 30
In order to solve this problem, we look at the graph (attached), and find the value of Money =80e + 5v at corner points to find the maximum value of money.
(e,v)=(0,0) >> Money = 80e+5v = 80*0+5*0 = 0
(e,v)=(0,20) >> Money = 80e+5v = 80*0+5*20 = 100
(e,v)=(20,0) >> Money = 80e+5v = 80*20+5*0 = 1600
(e,v)=(20,10) >> Money = 80e+5v = 80*20+5*10 = 1650 (maximum)
(e,v)=(10,20) >> Money = 80e+5v = 80*10+5*20 = 900
So Bob can make the
<u>most money = $1,650</u> when he makes and sell
e = <span>Gibson Explorer’s = 20
</span>v = Gibson Flying V’s = 10
Answer:
<em><u>478</u></em>
Step-by-step explanation:
1*10+32(2+4+6)+76+2^3
First parenthesis
1*10+32(12)+76+2^3
Next exponents
1*10+32(12)+76+8
Next multiplication
10+384+76+8
Then add
394+84
Add
478
Therefore, your answer would be <u><em>478</em></u>
X = 1/4, 5, -8
Hope this helps!
Answer:
2x-6 is the equation
Step-by-step explanation:
8x+6=54
subtract 6 from both sides
8x+6-6=54-6
8x=48
x=6