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goldfiish [28.3K]
3 years ago
5

Please answer it in two minutes

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
4 0

Answer:

IJ = 6

Step-by-step explanation:

This is a 30-60-90 triangle.

The ratio of the lengths of the sides is:

1 : sqrt(3) : 2

The short leg is the length of the long leg divided by sqrt(3).

The hypotenuse is twice the length of the short leg.

IK = JK/sqrt(3) = 3sqrt(3)/sqrt(3) = 3

IJ = 2IK = 2(3) = 6

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Step-by-step explanation:

4 0
2 years ago
Could someone help with this?
Citrus2011 [14]

the answer is 4 and 7                

3 0
3 years ago
The students in Todd's grade voted to select a guest speaker. 24 students voted for a famous athlete. The other 8 students in To
Colt1911 [192]

Answer:

75% of students voted for the athlete

Step-by-step explanation:

total number of students 24+8 = 32

24 out of 32 students chose the athlete

24/32 simplified = 3/4

3/4 = 75%

8 0
2 years ago
Which series of transformations will not map figure H onto itself
7nadin3 [17]

Answer:

D

Step-by-step explanation:

Given a square with vertices at points (2,1), (1,2), (2,3) and (3,2).

Consider option A.

1st transformation (x+0,y-2) will map vertices of the square into points

  • (2,1)\rightarrow (2,-1);
  • (1,2)\rightarrow (1,0);
  • (2,3)\rightarrow (2,1);
  • (3,2)\rightarrow (3,0).

2nd transformation = reflection over y = 1 has the rule (x,2-y). So,

  • (2,-1)\rightarrow (2,3);
  • (1,0)\rightarrow (1,2);
  • (2,1)\rightarrow (2,1);
  • (3,0)\rightarrow (3,2)

These points are exactly the vertices of the initial square.

Consider option B.

1st transformation (x+2,y-0) will map vertices of the square into points

  • (2,1)\rightarrow (4,1);
  • (1,2)\rightarrow (3,2);
  • (2,3)\rightarrow (4,3);
  • (3,2)\rightarrow (5,2).

2nd transformation = reflection over x = 3 has the rule (6-x,y). So,

  • (4,1)\rightarrow (2,1);
  • (3,2)\rightarrow (3,2);
  • (4,3)\rightarrow (2,3);
  • (5,2)\rightarrow (1,2)

These points are exactly the vertices of the initial square.

Consider option C.

1st transformation (x+3,y+3) will map vertices of the square into points

  • (2,1)\rightarrow (5,4);
  • (1,2)\rightarrow (4,5);
  • (2,3)\rightarrow (5,6);
  • (3,2)\rightarrow (6,5).

2nd transformation = reflection over y = -x + 7 will map vertices into points

  • (5,4)\rightarrow (3,2);
  • (4,5)\rightarrow (2,3);
  • (5,6)\rightarrow (1,2);
  • (6,5)\rightarrow (2,1)

These points are exactly the vertices of the initial square.

Consider option D.

1st transformation (x-3,y-3) will map vertices of the square into points

  • (2,1)\rightarrow (-1,-2);
  • (1,2)\rightarrow (-2,-1);
  • (2,3)\rightarrow (-1,0);
  • (3,2)\rightarrow (0,-1).

2nd transformation = reflection over y = -x + 2 will map vertices into points

  • (-1,-2)\rightarrow (4,3);
  • (-2,-1)\rightarrow (3,4);
  • (-1,0)\rightarrow (2,3);
  • (0,-1)\rightarrow (3,2)

These points are not the vertices of the initial square.

5 0
3 years ago
Given directed line segment PR, find the coordinates of Q on PR such that the ratio of PQ to QR is 2:1.
Alekssandra [29.7K]

Answer:

4/3, -3

Step-by-step explanation:

4 0
2 years ago
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