Two ships leave a harbor at the same time. one ship travels on a bearing upper s 12 degrees upper w at 13 miles per hour. the ot
her ship travels on a bearing upper n 75 degrees upper e at 10 miles per hour. how far apart will the ships be after 3 hours?
1 answer:
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The correct answer would be 
In order to solve for this you must first get the equation equal to 0.
<span>x^2=-5x-3 ----> add 5x to both sides.
x^2 + 5x = -3 ----> add 3 to both sides.
x^2 + 5x + 3 = 0
Now knowing this we can use the coefficients of each one in descending order of power as a, b and c.
a = 1 (because it is the coefficient to x^2)
b = 5</span> (because it is the coefficient to x)
c = 3 (because it is the end number)
Now we can plug these values into the quadratic equation.
And those would be your two answers.
In order to solve for this you must first get the equation equal to 0.
<span>x^2=-5x-3 ----> add 5x to both sides.
x^2 + 5x = -3 ----> add 3 to both sides.
x^2 + 5x + 3 = 0
Now knowing this we can use the coefficients of each one in descending order of power as a, b and c.
a = 1 (because it is the coefficient to x^2)
b = 5</span> (because it is the coefficient to x)
c = 3 (because it is the end number)
Now we can plug these values into the quadratic equation.
And those would be your two answers.