Answer: D. an angle is in standard position if the vertex is at the origin of a rectangular coordinate system and the initial side lies along the positive x-axis.
Answer:
Step-by-step explanation:
You can solve this two ways: insert the values into point-slope form and simplify to solve for y, converting it to slope-intercept form, <em>or</em><em> </em>insert the values into slope-intercept form, solve for b, and insert b. We'll do both :)
<em><u>Point-slope form:</u></em>
Where:
is the slope
and 
are corresponding coordinate points 
Insert the given values:
Solve for y. Expand the right sie using the distributive property:
Isolate the variable. Subtract 6 from both sides, canceling out the 6 on the left:
<em>OR</em>
<em></em>
<em><u>Slope-intercept form:</u></em>
Where:
- is the slope
is the y-intercept
and 
are corresponding coordinate points
Insert the given values:
Simplify the multiplication:
Solve for b. Add 10 to both sides, canceling out the 10 on the right:
The value of b is 4. Insert the appropriate information into the equation. When using slope-intercept form, you don't plug in the coordinate points:
:Done
The answer is f, non of the above.
To find the half of 2330, simply divide by 2 or 1/2.
Which gives you 1165.
Answer:
115° and 245°
Step-by-step explanation:
Given
cos x = - 0.4226
Since cos x < 0 then x is an angle in the second / third quadrants, thus
x = (0.4226) = 65° ← related acute angle , thus
x = 180° - 65° = 115° ← angle in second quadrant
x = 180° + 65° = 245° ← angle in third quadrant
Answer : 1⅖ft.²
<u>Given</u><u> </u><u>:</u><u>-</u>
- Print is 7/8 ft wide and 1⅗ ft long .
<u>To </u><u>Find</u><u> </u><u>:</u><u>-</u>
Here the length of the print is 1⅗ ft . So on converting this into improper fraction , we have ;
→ length = 1⅗ ft = (5*1+3)/5 ft = (5+3)/5ft = 8/5ft.
Also ,
→ breadth = 7/8ft .
We know that the area of a rectangle is ,
→ Area = length * breadth
On substituting the respective values,
→ Area = 8/5 ft. * 7/8ft
→ Area = 7/5 ft.²
After converting improper fraction into mixed fraction ,
→ Area = 1⅖ ft² .
<u>Henceforth</u><u> the</u><u> area</u><u> of</u><u> the</u><u> </u><u>print</u><u> </u><u>is </u><u>1</u><u>⅖</u><u>f</u><u>t</u><u>.</u><u>²</u><u> </u><u>.</u>
<em>I </em><em>hope</em><em> this</em><em> helps</em><em>.</em>
