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3 years ago

What is the slope or change of 6(x-y) =5(x+y)

Mathematics

1 answer:

scoundrel [369]3 years ago

3 0

6x - 6y = 5x + 5y ; / - 6x
We solve for y ;
-6y = -x + 5y ; / -5y
-y = -x ; / *(-1) ;
y = 1*x ;
The slope is 1.

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Greg made 27 ounces of potato salad to serve to 10 people at a picnic if each serving is the same size how much potato salad wip

kirza4 [7]

Answer:

Each person will get 2.7 ounces of potato salad.

Step-by-step explanation:

We are given that;

Total ounces of potato salad Greg made = 27 ounces

Number of persons to be served = 10 people

Now, we are told that each serving is the same size, thus it means each person will receive same size of potato salad.

Thus,

the amount received by each person = Total ounces of potato salad Greg made/total number of persons to be served.

So,

the amount received by each peron

= 27/10

= 2.7 ounces

Thus,

Each person will get 2.7 ounces of potato salad.

6 0

3 years ago

You and a friend go to surf taco for lunch. you order 3 soft tacos and 2 burritos and your total bill is 25. Your friend bill is

Salsk061 [2.6K]

Answer:

Step-by-step explanation:

Let the cost of one soft taco = s

Let the cost of one burrito = b

So we have this system

3s + 3b = 11.25

4s + 2b = 10.00 (1)

Divide the first equation through by 3 and we have that

s + b = 3.75 subtract b from both sides

s = 3.75 - b (2)

Sub (2) into (1) and we have

4 (3.75 - b) + 2b = 10.00 simplify

15 - 4b + 2b = 10.00

-2b + 15 =10.00 subtract 15 from both sides

-2b = - 5.00 divide both sides by -2

b = 2.50

And using (2)

s = 3.75 - 2.50 = 1.50

So... a soft taco 1.50 and a burrito is 2.50

6 0

2 years ago

Lines intersected by a transversal can never be parallel lines. True or false

gayaneshka [121]

Answer : True

When lines intersect they can't be parallel.!

5 0

3 years ago

Your family is installing a new square pool in the backyard. The existing patio has a side length of 8 feet. How much of the pat

trasher [3.6K]

The question is an illustration of perimeters.

The amount of patio to remove to install the pool is 8 feet.

From the question, we have:

$\mathbf{Length\ of\ the\ pool = 8}$

$\mathbf{Length\ of\ walkway = 1}$

The perimeter of the patio is:

$\mathbf{P_p = 4 \times Length\ of\ the\ pool}$

$\mathbf{P_p = 4 \times 8}$

$\mathbf{P_p = 32}$

A 1ft walkway means that;

1ft would be subtracted from both sides of the patio before installing the pool

So, the perimeter of the patio in terms of the length of the pool is:

$\mathbf{P_p = 4 \times (x +2)}$

Equate both expressions

$\mathbf{P_p = P_p}$

$\mathbf{4 \times (x +2) = 32}$

Divide both sides by 4

$\mathbf{x +2 = 8}$

Subtract 2 from both sides

$\mathbf{x = 6}$

So, the perimeter of the pool is:

$\mathbf{P_{pool} = 4 \times 6}$

$\mathbf{P_{pool} = 24}$

The amount of patio to remove is:

$\mathbf{Amount = P_p - P_{pool}}$

So, we have:

$\mathbf{Amount = 32 - 24}$

$\mathbf{Amount = 8}$

Hence, 8ft of the patio would be removed to install the pool

<em>See attachment for illustration</em>