Hello!
To find the maximum value of the function f(x) = -3(x - 10)(x - 4), the easiest way is to find the vertex using the formula: x = -b/2a.
Firstly, we need to simplify f(x).
f(x) = -3(x - 10)(x - 4)
f(x) = -3(x² - 14x + 40)
f(x) = -3x² + 42x + -120
Since the equation f(x) is now simplified to standard form, we can find the vertex.
a = -3, b = 42, and c = -120
x = -(42)/2(-3) = -42/-6 = 7
Then, we substitute 7 into the the function f(x) = -3(x - 10)(x - 4), or
f(x) = -3x² + 42x + -120, to find the y-value of the vertex.
f(x) = -3(7 - 10)(7 - 4)
f(x) = -3(-3)(4)
f(x) = 27
The vertex of f(x) is (7, 27).
Therefore, the maximum x-value for the function f(x) is 7.
1200 as you would round it down to 100 a week so you would do 100x12
Answer: i believe the answer is 4).
Step-by-step explanation:
Because x= + 
+ 6
Answer: 2
Step-by-step explanation: x^2+8/x^2-5x+6
= x4 - 5x3 + 6x2 + 8
/x^2=2
Find roots (zeroes) of : F(x) = x4 - 5x3 + 6x2 + 8
See theory in step 3.2
In this case, the Leading Coefficient is 1 and the Trailing Constant is 8.
The factor(s) are:
of the Leading Coefficient : 1
of the Trailing Constant : 1 ,2 ,4 ,8
Let us test ....
P Q P/Q F(P/Q) Divisor
-1 1 -1.00 20.00
-2 1 -2.00 88.00
-4 1 -4.00 680.00
-8 1 -8.00 7048.00
1 1 1.00 10.00
2 1 2.00 8.00
4 1 4.00 40.00
8 1 8.00 1928.00
2
