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Artemon [7]
3 years ago
11

Suppose the heights of adult men are normally distributed. The heights of a sample of 30 men are shown below, in inches. 65, 83,

69, 67, 69, 67, 67, 72, 85, 68, 73, 65, 67 ,65, 72, 71, 67, 73, 68, 72, 61, 75, 66, 78, 65, 71, 68, 76, 67, 68. What is the mean and standard deviation of this sample? a. mean: 70 standard deviation: 4.626 c. mean: 70 standard deviation: 5.228 b. mean: 67 standard deviation: 4.626 d. mean: 67 standard deviation: 5.228
Mathematics
2 answers:
sweet [91]3 years ago
5 0

Answer: Mean-70. Standard Deviation-5.228

Step-by-step explanation:

ololo11 [35]3 years ago
5 0

Answer: Mean- 70

Standard deviation- 5.228

Step-by-step explanation: C

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Write and solve an equation to find the value of x and a missing angle in each triangle below. Use the number bank to help you c
jolli1 [7]

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2 years ago
​Joe's annual income has been increasing each year by the same dollar amount. The first year his income was ​$17 comma 90017,900
Vedmedyk [2.9K]

Answer:

In 17th year, his income was $30,700.

Step-by-step explanation:

It is given that the income has been increasing each year by the same dollar amount. It means it is linear function.

Income in first year = $17,900

Income in 4th year = $20,300

Let y be the income at x year.

It means the line passes through the point (1,17900) and (4,20300).

If a line passes through two points (x_1,y_1) and (x_2,y_2), then the equation of line is

y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)

The equation of line is

y-17900=\frac{20300-17900}{4-1}(x-1)

y-17900=\frac{2400}{3}(x-1)

y-17900=800(x-1)

y-17900=800x-800

Add 17900 on both sides.

y=800x-800+17900

y=800x+17100

The income equation is y=800x+17100.

Substitute y=30,700 in the above equation.

30700=800x+17100

Subtract 17100 from both sides.

30700-17100=800x

13600=800x

Divide both sides by 800.

\frac{13600}{800}=x

17=x

Therefore, in 17th year his income was $30,700.

5 0
3 years ago
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