Answer:
sec theta = (sqrt24/5) cos theta = -2/5 tan theta = (-[sqrt 21]/2) sec theta = 5/2 csc theta = (5sqrt21)/21 cot theta = (-2sqrt21)/21
Step-by-step explanation:
During the problem, secx = -5/2, we can assume that as cos = -2/5. -2 = x. 5 = r. find for Y with: x^2+y^2=r^2. After that, plug in for the variables and you get all the answers. Rationalize the square roots, don't forget.
Answer:
The air is .6m^3
Step-by-step explanation:
The volume of a cube is
V = s^3 where s is the side length
The volume of the tank is
V = 1^3 = 1 m^3
The volume of the water is 1 by 1 by .4
V = l*w*h
= 1 *1*.4
= .4 m^3
The difference must be filled by air
1- .4 = .6 m^3
The air is .6m^3
Answer:
-x+4
Step-by-step explanation:
I could be wrong.
Y+1=3(x+1)
if you need to simplify to slope intercept form then y=3x+2
