Answer:
i think that would be (2,0)
Answer:
<h2>y=7x-47</h2>
Step-by-step explanation:
Please write x^2, not x2.
If you stretch the graph of y=x^2 vertically by a factor of 4, the resulting graph represents the quadratic function y = 4x^2. It's still a parabola, but appears to be thinner.
This particular question is about horizontal stretching, however. Stretching the graph horizontally by a factor of 4 results in the new function g(x) = (x/4)^2. Try graphing x^2 and also (x/4)^2 on the same set of axes to observe this phenomenon.
There are several approaches.
(5/3)x^2 - 5 = 0 has the coefficients a=5/3, b=0 and c = -5.
Thus, the quadratic formula would be appropriate here:
-0 plus or minus sqrt(0^2 - 4(5/3)(-5) )
x = -------------------------------------------------------
2(5/3)
plus or minus sqrt(100/3)
= ------------------------------------
10/3
3 10
= ------* ----------- = sqrt(3) (answer)
10 sqrt(3)
