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4vir4ik [10]
3 years ago
9

Write the exponential function that passes through the points (3, 10) and (5, 40)

Mathematics
1 answer:
tigry1 [53]3 years ago
6 0

Answer:

  y = (5/4)2^x

Step-by-step explanation:

The function value increases by a factor of 40/10 = 4 when x increases by 2. The function can be written as ...

  y = (reference value)·(growth factor)^((x -reference)/(change in x for growth factor))

  y = 10·4^((x-3)/2) . . . . . . using point (3, 10) as a reference

This can be simplified to ...

  y = 10·2^(x -3) = 10/8·2^x

  y = (5/4)2^x

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8 + 8r = 3 + 3r can anyone can help me out​
MAVERICK [17]

Answer:r = -1

Step-by-step explanation:

8+8r-(3+3r)=0

We add all the numbers together, and all the variables

8r-(3r+3)+8=0

We get rid of parentheses

8r-3r-3+8=0

We add all the numbers together, and all the variables

5r+5=0

We move all terms containing r to the left, all other terms to the right

5r=-5

r=-5/5

r=-1

Hope this helps

6 0
3 years ago
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Lena [83]

Answer:

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5. prudence

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Step-by-step explanation:

6 0
3 years ago
What’s the correct answer for this? Select the ones that apply
faust18 [17]
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7 0
3 years ago
If f(x) = 5x - 12, what is f2)?<br> O A. -22<br> O B. 10<br> O C. -2<br> D. 2
Step2247 [10]

Answer:

C , -2

Step-by-step explanation:

Replace X in the equation with 2

f(2) = 5(2) - 12

f(2) = 10-12

f(2) = -2

6 0
3 years ago
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A lake has a large population of fish. On average, there are 2,400 fish in the lake, but this number can vary by as much as 155.
AleksAgata [21]

Answer:

Minimum population of fish in lake = 2400 - 155 = 2245

Maximum population of fish in lake = 2400 + 155 = 2555

Step-by-step explanation:

population of fish in lake = 2400

Variation of fish = 155

it means that while current population of fish is 2400, the number can increase or decrease by maximum upto 155.

For example

for increase

population of fish can 2400 + 2, 2400 + 70, 2400 + 130 etc

but it cannot be beyond 2400 + 155.

It cannot be 2400 + 156

similarly for decrease

population of fish can 2400 - 3, 2400 - 95, 2400 - 144 etc

but it cannot be less that 2400 - 155.

It cannot be 2400 - 156

Hence population can fish in lake can be between 2400 - 155 and 2400 + 155

minimum population of fish in lake = 2400 - 155 = 2245

maximum population of fish in lake = 2400 + 155 = 2555

4 0
3 years ago
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