Answer:
Step-by-step explanation:
Remark
The formula for this is
Heat = m * c * Δt
Givens
Heat = unknown
m = 200 grams
c = 4.184 Joules / grams oC
Δt = the change in temperature = 35.7 - 22.3 = 13.4
Solution
Heat = 200 * 4.184 * 13.4
Heat = 11213 Joules
Heat = 11.2 Kj
It's hard to get the correct number of sig digs because the 200 is not qualified in any way.
Part 2.
This can really puzzle you until you know that heat given up = the heat taken on. The heat taken on was 11.2 Kj. The Butane lighter must have given that heat on.
Heat of Combustion = Heat Given Up / Number grams burned.
Heat of Combustion = 11.2 Kj / 0.23 grams
Heat of Combustion = 48.8 Kj / gram
Answer:
(2,21)
Step-by-step explanation:
y = 10.5x
plug 2 for x in the equation
y = 10.5(2)
then multiply 2 by 10.5
y=21
hahahah hfguiyfewkuygf 30 points i wnt it not 5
Answer:
73
Step-by-step explanation:
to find the mean you need to add up all grades and divide if by the number of terms you added
(82 + 88 + x) ÷ 3 = 69 (since we don't know the third grade let's call it x)
170 + x = 69 × 3
x = 37
if the digits transposed the the actual grade would be 73
