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Softa [21]
2 years ago
10

200 people are asked about three brands of beverages Coffee, Tea and Chocolate. 36 like Coffee only, 46 like Coffee but not Tea,

52 like Coffee, 16 like Tea and Chocolate, 96 like Chocolate, 16 like Coffee and Chocolate while a total of 108 like one and only one of the beverages. Required i) Calculate the number of people like black coffee? (3 marks)
ii) How many people don’t like any of the drinks?
Mathematics
1 answer:
xxTIMURxx [149]2 years ago
4 0
I) 96 people ii) tea choccy
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6.23+(-12.49)-2.6<br> What's the answer?
Mila [183]
6.23+ -12.49 -2.6= 6.23+ -12.49+ -2.6
-6.26+-2.6= -8.86
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3 years ago
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Solve the system: <br> 2/x - 3/y =-5; 4/x + 6\y =14
sertanlavr [38]

The solution is x = 2 \text{ and } y = \frac{1}{2}

<em><u>Solution:</u></em>

Let us assume,

a = \frac{1}{x}\\\\b = \frac{1}{y}

<em><u>Given system of equations are:</u></em>

\frac{2}{x} - \frac{3}{y} = -5

\frac{4}{x} + \frac{6}{y} = 14

<em><u>Rewrite the equation using "a" and "b"</u></em>

2a - 3b = -5 ------------ eqn 1

4a + 6b = 14 -------------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

<em><u>Multiply eqn 1 by 2</u></em>

2(2a - 3b = -5)

4a - 6b = -10 ------------- eqn 3

<em><u>Add eqn 2 and eqn 3</u></em>

4a + 6b = 14

4a - 6b = -10

( - ) --------------------

8a = 4

a = \frac{4}{8}\\\\a = \frac{1}{2}

Substitute a = 1/2 in eqn 1

2(\frac{1}{2}) -3b = -5\\\\1 - 3b = -5\\\\3b = 6\\\\b = 2

Now let us go back to our assumed values

Substitute a = 1/2 in assumed values

a = \frac{1}{x}\\\\\frac{1}{2} = \frac{1}{x}\\\\x = 2

Substitute b = 2 in assumed value

b = \frac{1}{y}\\\\2 = \frac{1}{y}\\\\y = \frac{1}{2}

Thus the solution is x = 2 \text{ and } y = \frac{1}{2}

3 0
3 years ago
Find the absolute value<br><br> -5/6|
Nadya [2.5K]

Answer:

5/6 OR 0.83 (with the three repeating)

Hope that helps!

Step-by-step explanation:

5 0
3 years ago
Simplify 2y-6x+5+4y<br> What is the answer?
Misha Larkins [42]

Answer:

Answer = −6x+6y+5

3 0
3 years ago
“Drew has 50 red, green, and blue marbles. He has six more red marbles than blue marbles and four fewer green marbles than blue
kolezko [41]
(1) R+G+B=50
(2) R=B+6
(3) G=B-4 so substitute G in (1)
R+B-4+B=50 substitute (2) in here
B+6+B-4+B=50 group like terms and solve
3B+2=50
3B=50-2
B=48/3=16 substitute in (2) and (3)
R=16+6=22
G=16-4=12
Check
22+12+16=50✅


8 0
3 years ago
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