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Step2247 [10]
3 years ago
7

Solve the question belo , thanks

Mathematics
1 answer:
Eddi Din [679]3 years ago
4 0

Answer:

The coordinates of N are (-1,-6)

Step-by-step explanation:

M is the midpoint of AN

A(-7,4) and M(-4,-1)

The distance AM is given by (-4--7,-1 - 4) = (3,-5)

Since AM = MN;

N = M(-4,-1) + (3,-5)

N = (-4 + 3,-1 + -5)

This gives the coordinates of N to be;

N(-1,-6)

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On a coordinate plane, a curved line crosses the y-axis at (0, 1), crosses the x-axis at (.25, 0), turns at point (2, negative 3
Artyom0805 [142]

Answer:

All real numbers greater than or equal to -3

Step-by-step explanation:

we know that

The curved line could be a vertical parabola opening upwards with vertex at (2,-3)

The vertex is a minimum

The y-intercept is the point (0,1)

The x-intercepts are the points (0.25,0) and (3.75,0)

so

The domain is the interval -----> (-∞,∞)

All real numbers

The range is the interval ----> [-3,∞)

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6 0
2 years ago
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What are the real and complex solutions of the polynomial equation? x^4-41x^2=-400
tankabanditka [31]
<h3>Answer:</h3>

The real solutions are -5, -4, 4, 5. There are no complex solutions.

<h3>Step-by-step explanation:</h3>

The equation ...

... x^4 -41x^2 +400 = 0

can be factored as ...

... (x^2 -16)(x^2 -25) = 0

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3 years ago
Which of the following correctly describes the domain of the function shown
labwork [276]

Option D:

\{x: x \neq 1\} is the domain of the function.

Solution:

Given function is

$r(x)=\frac{2 x}{x-1}

<u>To find the domain of the function:</u>

Option A: \{x: x \neq 0\}

Substitute x = 0 in r(x).

$r(0)=\frac{2 \times 0}{0-1}=0

If x = 0, then r(0) = 0

So that x ≠ 0 is false.

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Substitute x = 1 in r(x).

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It is indeterminate.

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Substitute x = 1 in r(x).

$r(1)=\frac{2 \times 1}{1-1}=\frac{2}{0}

It is indeterminate.

So, \{x: x \neq 1\} is the domain of the function.

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