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Genrish500 [490]
3 years ago
5

Given that x is a nonnegative number, a student conjectured that x + 3 < x2.

Mathematics
1 answer:
nadya68 [22]3 years ago
6 0

Answer:

C (x = 2)

Step-by-step explanation:

Since x is a non-negative number, A and B are eliminated.

This leaves C and D.

C: x = 2,

2 + 3 < 2^2

5 < 4 is false.

So C would be a counterexample.

Hope this helps!

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Answer:

Step-by-step explanation:

hello,

for ax^2+bx+c=0

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so here

\Delta = b^2-4*(-4)*(-11)=b^2-176

to have two complex solutions we need \Delta < 0\\

so b^2

b < \sqrt{176}=13.266...

for instance we can take b = 0

hope this helps

4 0
4 years ago
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Answer:

Hello!

________________________

5c + 16.5 = 13.5 + 10c

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