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Serhud [2]
3 years ago
14

Write an equation in slope - intercept form for the line that satisfies each set of conditions. answers only 24. slope 0.25, pas

ses through (0,4) 26. slope 3/2, passes through (-5,1) 28. slope 4, passes through the origin 30. passes through (7,1) and (7,8) 32. passes through (-2,-3) and (0,0) 34. x- intercept = 1/3, y- intercept = -1/4
Mathematics
1 answer:
Montano1993 [528]3 years ago
3 0
24.) y = mx + b
       slope(m) = 0.25
       (0,4)...x = 0 and y = 4
       now we sub and find b, the y int
       4 = 0.25(0) + b
       4 = b
       so ur equation is : y = 0.25x + 4

26.) y = mx + b
       slope(m) = 3/2
       (-5,1)....x = -5 and y = 1
        sub and find b, the y int
        1 = 3/2(-5) + b
         1 = - 15/2 + b
         1 + 15/2 = b
          2/2 + 15/2 = b
          17/2 = b
          ur equation is : y = 3/2x + 17/2

28.) y = mx + b
       slope(m) = 4
       (0,0)...x = 0 and y = 0
        time to sub
        0 - 4(0) + b
        0 = b
        so ur equation is : y = 4x + 0.....or just y = 4x

30.) (7,1)(7,8)....notice how the x's are the exact same number....this           
        means that ur line is a vertical line with a slope that is undefined.
        ur equation is : x = 7

32.) (-2,-3)(0,0)
       slope = (0 - (-3) / (0 - (-2) = (0 + 3) /(0 + 2) = 3/2
       
         y = mx + b
         slope(m) = 3/2
         (0,0)...x = 0 and y = 0
          sub
         0 = 3/2(0) + b
         0 = b
         ur equation is : y = 3/2x + 0 or just y = 3/2x

34.) (1/3,0)(0,-1/4)
        slope = (-1/4 - 0) / (0 - 1/3) = (-1/4)/(-1/3) = -1/4 * -3 = 3/4
     
         y = mx + b
         slope(m) = 3/4
         (0,-1/4)...x = 0 and y = -1/4
          sub
          -1/4 = 3/4(0) + b
           -1/4 = b
           so ur equation is : y = 3/4x - 1/4



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