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3 years ago

Given the function F(x)=3x+2 f(x)=8 find the following f(x)=8

Mathematics

1 answer:

sergiy2304 [10]3 years ago

7 0

I believe the answer is 26. But I’m new to this I just learned this last week.

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The equation of line m is 3x−5y=−4

vaieri [72.5K]

Slope of this line, -5y = -3x - 4
y = 3/5x + 4/5
So, slope of line which is perpendicular = -5/3 [reciprocal & opposite ]

In short, Your Answer would be -5/3

Hope this helps!

4 0

3 years ago

Can someone explain this for me ? :)

ruslelena [56]

34! Find the area of each of the six sides and then add them up:)

7 0

3 years ago

PLEASE HELP! I am having trouble with both questions

schepotkina [342]

Answer:

someone had the same exact question i just helped him on it sub 4 for x and 1 for h

Step-by-step explanation:

6 0

2 years ago

43 = 20 + z/3 please help

BabaBlast [244]

Answer:

z = 69

Step-by-step explanation:

43 - 20 = z/ 3

23 = $\frac{z}{3}$

cross multiply

z = 23 x 3

z =69

3 0

3 years ago

5. Find the general solution to y'''-y''+4y'-4y = 0

CaHeK987 [17]

For any equation,

$a_ny^(n)+\dots+a_1y'+a_0y=0$

assume solution of a form, $e^{yt}$

Which leads to,

$(e^{yt})'''-(e^{yt})''+4(e^{yt})'-4e^{yt}=0$

Simplify to,

$e^{yt}(y^3-y^2+4y-4)=0$

Then find solutions,

$\underline{y_1=1}, \underline{y_2=2i}, \underline{y_3=-2i}$

For non repeated real root y, we have a form of,

$y_1=c_1e^t$

Following up,

For two non repeated complex roots $y_2\neq y_3$ where,

$y_2=a+bi$

and,

$y_3=a-bi$

the general solution has a form of,

$y=e^{at}(c_2\cos(bt)+c_3\sin(bt))$

Or in this case,

$y=e^0(c_2\cos(2t)+c_3\sin(2t))$

Now we just refine and get,

$\boxed{y=c_1e^t+c_2\cos(2t)+c_3\sin(2t)}$

Hope this helps.

r3t40

5 0

3 years ago