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mina [271]
3 years ago
13

How many solutions does the following system of equations have? y=5/2x+2 and 2y=5x+8

Mathematics
1 answer:
Yuki888 [10]3 years ago
3 0

Answer:

No solutions.

Step-by-step explanation:

y = 5/2x + 2

2y = 5x + 8

Plug the first equation into the second.

2(5/2x + 2) = 5x +8

5x + 4 = 5x + 8

<em>5x + 4 cannot equal 5x + 8, so this system of equations has no solutions.</em>

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(10 points) <br> Solve for x. Assume that the lines which appear to be tangent are tangent
Ganezh [65]

The two tangent lines for each circle are the same length. Set the equations to equal and solve for x.

1. 4x + 3 = 3x +12

Subtract 3x from each side:

x +3 = 12

Subtract 3 from both sides:

x = 9

2. -2 + x = 2x -7

Subtract 2x from both sides:

-2 - x =  -7

Add 2 to each side:

-x = -5

Multiply both sides by -1:

x = 5

8 0
3 years ago
Write<br> 9/18<br> in lowest terms
kogti [31]

Answer:

1/2

Step-by-step explanation:

7 0
3 years ago
Chelsey put for $450 into an account with a simple interest rate of 2.5% when she withdrew the money she had earned a total of $
fgiga [73]

Answer:

5.66 years

Step-by-step explanation:

450 x 1.025^(n) = 450 + 67.50

450 x 1.025^(n) = 517.50

1.025^(n) =(517.50 / 450)

1.025^(n) = 1.15

n = ln(1.15) / ln(1.025)

n = 5.66

6 0
3 years ago
A circular swimming pool has a radius of 28ft. There is a path all the way around the pool that's 4ft wide. A fence is going to
Natalka [10]

Answer:

Therefore 200.96 ft.of fencing are needed to go around the pool path.

Step-by-step explanation:

Given, a circular swimming pool has a radius of 28ft. There is a path all the way around the pool. The width of the path 4 ft.

The radius of the outside edge the pool path is

= Radius of the pool + The width of the path

= (28+4) ft

= 32 ft.

To find the length of fencing, we need to find the circumference of outside the pool path.

Here r= 32 ft

The circumference of outside edge of the pool path

=2\pi r

=(2\times 3.14 \times 32) ft

=200.96 ft.

Therefore 200.96 ft.of fencing are needed to go around the pool path.

3 0
3 years ago
Which expression is equivalent to square root 55x^7 y^6/11x^11 y^8? Assume x &gt; 0 and y &gt; 0.
morpeh [17]
The first step for solving this expression is to reduce the fraction with 11.
\sqrt{ \frac{5 x^{7} y^{6}  }{ x^{11}  y^{8} } }
Now reduce the fraction with x^{7}.
\sqrt{ \frac{5 y^{6} }{ x^{4} y^{8}  } }
Reduce the fraction one more time with y^{6}.
\sqrt{ \frac{5}{ x^{4} y^{2}  } }
To take the root of a fraction,, we must take the root of the numerator and denominator separately. This rule will change the expression to the following:
\frac{ \sqrt{5} }{ x^{2} y}
Since we cannot simplify this fraction any further,, the final answer is going to be \frac{ \sqrt{5} }{ x^{2} y}.
Let me know if you have any further questions.
:)
3 0
3 years ago
Read 2 more answers
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