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3 years ago

How many solutions does the following system of equations have? y=5/2x+2 and 2y=5x+8

Mathematics

1 answer:

Yuki888 [10]3 years ago

3 0

Answer:

No solutions.

Step-by-step explanation:

y = 5/2x + 2

2y = 5x + 8

Plug the first equation into the second.

2(5/2x + 2) = 5x +8

5x + 4 = 5x + 8

5x + 4 cannot equal 5x + 8, so this system of equations has no solutions.

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(10 points) Solve for x. Assume that the lines which appear to be tangent are tangent

Ganezh [65]

The two tangent lines for each circle are the same length. Set the equations to equal and solve for x.

1. 4x + 3 = 3x +12

Subtract 3x from each side:

x +3 = 12

Subtract 3 from both sides:

x = 9

2. -2 + x = 2x -7

Subtract 2x from both sides:

-2 - x = -7

Add 2 to each side:

-x = -5

Multiply both sides by -1:

x = 5

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3 years ago

Write 9/18 in lowest terms

kogti [31]

Answer:

1/2

Step-by-step explanation:

7 0

3 years ago

Chelsey put for $450 into an account with a simple interest rate of 2.5% when she withdrew the money she had earned a total of $

fgiga [73]

Answer:

5.66 years

Step-by-step explanation:

450 x 1.025^(n) = 450 + 67.50

450 x 1.025^(n) = 517.50

1.025^(n) =(517.50 / 450)

1.025^(n) = 1.15

n = ln(1.15) / ln(1.025)

n = 5.66

6 0

3 years ago

A circular swimming pool has a radius of 28ft. There is a path all the way around the pool that's 4ft wide. A fence is going to

Natalka [10]

Answer:

Therefore 200.96 ft.of fencing are needed to go around the pool path.

Step-by-step explanation:

Given, a circular swimming pool has a radius of 28ft. There is a path all the way around the pool. The width of the path 4 ft.

The radius of the outside edge the pool path is

= Radius of the pool + The width of the path

= (28+4) ft

= 32 ft.

To find the length of fencing, we need to find the circumference of outside the pool path.

Here r= 32 ft

The circumference of outside edge of the pool path

= $2\pi r$

$=(2\times 3.14 \times 32) ft$

=200.96 ft.

Therefore 200.96 ft.of fencing are needed to go around the pool path.

3 0

3 years ago

Which expression is equivalent to square root 55x^7 y^6/11x^11 y^8? Assume x > 0 and y > 0.

morpeh [17]

The first step for solving this expression is to reduce the fraction with 11.
$\sqrt{ \frac{5 x^{7} y^{6} }{ x^{11} y^{8} } }$
Now reduce the fraction with $x^{7}$ .
$\sqrt{ \frac{5 y^{6} }{ x^{4} y^{8} } }$
Reduce the fraction one more time with $y^{6}$ .
$\sqrt{ \frac{5}{ x^{4} y^{2} } }$
To take the root of a fraction,, we must take the root of the numerator and denominator separately. This rule will change the expression to the following:
$\frac{ \sqrt{5} }{ x^{2} y}$
Since we cannot simplify this fraction any further,, the final answer is going to be $\frac{ \sqrt{5} }{ x^{2} y}$ .
Let me know if you have any further questions.
:)

3 0

3 years ago

Read 2 more answers