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Taya2010 [7]
4 years ago
8

Is x + 2 a factor of x^20 - 4x^18 + 3x - 6

Mathematics
1 answer:
KiRa [710]4 years ago
5 0

Answer: (x-2) is not a factor

Step-by-step explanation:

x^20 - 4x^18 +3x - 6 = 0 is a polynomial.

To test if (x + 2) is a factor, we are to use factor theorem

Make x the subject of the formula

x + 2 = 0

x = 0 - 2

x = -2

Put x = -2 into the equation. If the result on both the left hand side and right hand side is 0, then (x + 2) is a factor

(-2)^20 - 4(-2)^18 + 3(-2) - 6 = 0

1048576 - 4(262144) -6 -6 =0

1048576 - 1048576 -12 = 0

0 -12 = 0

-12 =0

Since LHS is not equal to RHS. (x+2) is not a factor of the equation

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PLEASE HELP ME I BEG I REALLY NEED HELP WITH THIS PROBLEM!
lozanna [386]
Area = length x width

x² + 12x = l * x


A.  

First, you factor x from x² + 12x

x^{2} +12x=x(x+12)

area = x (x+12)

area = (x+12) * x

Length = x + 12



B.

If x = 10,
l = x + 12 = 10 +12 = 22
length = 22
and
Area = x² + 12x = 10² + 12(10) = 100 + 120 = 220
area = 220
        

Hope this helps :)
6 0
3 years ago
Help pleasee thank you so much in advance
Solnce55 [7]

Answer:

120

Step-by-step explanation:

180 subtract 60 equals 120

6 0
3 years ago
Read 2 more answers
A Party Store sells large plates in packs of 12 and small plates in packs of 8. In order to have an equal number of both, what i
erik [133]

Answer:

8 12 packs and 12 8 packs.

Step-by-step explanation:

6 0
3 years ago
Find the area of a rectangle 4 3/4 feet long and 2 feet long
omeli [17]

Answer:

9.5 ft^2

Step-by-step explanation:

It’s just 4.75 * 2

7 0
3 years ago
There are 4 people at a party. Consider the random variable X=’number of people having the same birthday ’ (match only month, N=
yulyashka [42]

Answer:

S = {0,2,3,4}

P(X=0) = 0.573 , P(X=2) = 0.401 , P(x=3) = 0.025, P(X=4) = 0.001

Mean = 0.879

Standard Deviation = 1.033

Step-by-step explanation:

Let the number of people having same birth month be = x

The number of ways of distributing the birthdays of the 4 men = (12*12*12*12)

The number of ways of distributing their birthdays = 12⁴

The sample space, S = { 0,2,3,4} (since 1 person cannot share birthday with himself)

P(X = 0) = \frac{12P4}{12^{4} }

P(X=0) = 0.573

P(X=2) = P(2 months are common) P(1 month is common, 1 month is not common)

P(X=2) = \frac{3C2 * 12P2}{12^{4} } + \frac{4C2 * 12P3}{12^{4} }

P(X=2) = 0.401

P(X=3) = \frac{4C3 * 12P2}{12^{4} }

P(x=3) = 0.025

P(X=4) = \frac{12}{12^{4} }

P(X=4) = 0.001

Mean, \mu = \sum xP(x)

\mu = (0*0.573) + (2*0.401) + (3*0.025) + (4*0.001)\\\mu = 0.879

Standard deviation, SD = \sqrt{\sum x^{2} P(x) - \mu^{2}}  \\SD =\sqrt{ [ (0^{2} * 0.573) + (2^{2}  * 0.401) + (3^{2} * 0.025) + (4^{2} * 0.001)] - 0.879^{2}}

SD = 1.033

4 0
3 years ago
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