Answer:
Look hard but ill see what i can do to help you Simplify:
AD = 2 BC
⇒
Area of the regular hexagon(A) is given by:
where, s is the side of the regular hexagon.
Substitute the given values we have;
Step-by-step explanation:
The equation is d = 67*d (Distance = speed*time).
The table is
h d
1 67
2 134
3 201
4 268
.......
Easy peasy
the average rate of change in section A is the slope from (1,g(1)) to (2,g(2))
the average rate of chagne in section B is the slope from (3,g(3)) to (4,g(4))
A.
section A
g(1)=4(3)^1=12
g(2)=4(3)^2=4(9)=36
slope=(36-12)/(2-1)=24/1=24
section B
g(3)=4(3)^3=4(27)=108
g(4)=4(3)^4=4(81)=324
slope=(324-108)/(4-3)=216/1=216
section A has an average rate of change of 24
section B has an average rate of change of 216
Use Bidmas, solve all the inner brackets (), with first division, then multiplication then addition then subtraction