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Mkey [24]
3 years ago
5

Estimate the sum for 1,537 times 242 then find the sum

Mathematics
2 answers:
oksano4ka [1.4K]3 years ago
6 0

Answer: Two values are 369600 and 300000.

Step-by-step explanation:

If we rounding the integers to nearest  ones ,

1537 \text{change into }1540\\\\242\text{ change into }240\\\\So,\\\text{Sum will be }\\=1540\times 240\\=369600

If we rounding the integers to nearest tens,

1537\text{ changes to }1500\\242\text{ changes to }200\\So,\\\text{Sum will be }\\=1500\times 200\\=300000

Hence, by estimation, we get

Two values from above two cases are 369600 and 300000.

Furkat [3]3 years ago
5 0
It says to estimate first 1,537 turns to 2,000 because the 5 is 5 or more so the 1 becomes 2 and everything else is zeros. Now multiply 2000x 242=484,000 is the Estimation. Now find the correct product for 1,537x242=371,954
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Step-by-step explanation:

Problem 1:

Multiply Equation 1 by 4, keep Equation 2 the same.

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Problem 1 Answer:

Equivalent system: 4x+4y=32, x-y=2; solution: x=5, y=3

Problem 2:

Keep Equation 1 the same. Add 1 and 2.

To add an equation, add the left sides together, and then the rights.

so: x+y=8 + x-y=2 gives us: 2x=10

solve for x ---> 2x/2=10/2--->x=5

plug x into x+y=8--->5+y=8--->y=3

Problem 2 answer:

Equivalent system: x+y=8, 2x=10; solution:x=5, y=3

Problem 3:

Subtract Equation 2 from 1, and keep 2 the same.

To subtract an equation, subtract the left sides, then the rights. We are subtracting 1<em> from </em>2, so its 2-1.

x-y=2 - x+y=8 gives us: -2y=-6

Solve for y by dividing by -2-->-2y/-2=-6/-2---> y=3

Plug into x-y=2---> x-3=2---> x=5

Problem 3 answer:

Equivalent system: -2y=-6, x-y=2; solution: x=5, y=3

Problem 4:

Multiply the sum of Equation 1 and 2 by a factor of 3. Keep equation 2 the same.

First we add 1 and 2: (we did this earlier) ---> 2x=10 ---> now we multiply it all by 3---> 2x*(3)=10*(3)---> this gives us: 6x=30---> now divide by 6 to solve for x: 6x/6=30/6 gives us: x=5

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Problem 4 answer:

Equivalent system: 6x=30, x-y=2; solution: x=5, y=3

______

Quick Tip: One thing inherent of Equivalent systems is that they have the same set of solutions. Thus, we know the systems are equivalent when they have the same set of solutions for x and y. Moreover, you don't need to solve every time after you attempt to find an equivalent system, instead, just plug in the values found in problem 1 to each new set of equations to test if they are equivalent.

If we find x=5 and y=3 for x+y=8 and x-y=2, then all we have to do is plug them in to 6x=30 and -2y=-6 to see if they are equivalent.

6(5)=30 ---> true

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