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Marina CMI [18]

2 years ago

12

Uwu this isnt a test but its practiceee

1 answer:

igor_vitrenko [27]2 years ago

4 0

<u>Answer</u>: B, (-3/2, -1)

<u>Step-by-step explanation:</u>

When you use the midpoint formula, (x1+x2/2 , y1+y2/2) you end up taking one away from -4, and dividing it by 2 (-3/2), and when you add 2 to -4, you get -2, divided by 2, is -1.

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What transformations are needed to change the parent cosine function to y=3cos(10(x-pi))?

juin [17]

Answer:

The graph of $y=cos(x)$ is:

*Stretched vertically by a factor of 3

*Compressed horizontally by a factor $\frac{1}{10}$

*Moves horizontally $\pi$ units to the rigth

The transformation is:

$y=3f(10(x-\pi))$

Step-by-step explanation:

If the function $y=cf(h(x+b))$ represents the transformations made to the graph of $y= f(x)$ then, by definition:

If $0$ then the graph is compressed vertically by a factor c.

If $|c| > 1$ then the graph is stretched vertically by a factor c

If $c$ then the graph is reflected on the x axis.

If $b> 0$ The graph moves horizontally b units to the left

If $b$ The graph moves horizontally b units to the rigth

If $0$ the graph is stretched horizontally by a factor $\frac{1}{h}$

If $h> 1$ the graph is compressed horizontally by a factor $\frac{1}{h}$

In this problem we have the function $y=3cos(10(x-pi))$ and our parent function is $y = cos(x)$

The transformation is:

$y=3f(10(x-\pi))$

Then $c =3>1$ and $b =-\pi < 0$ and $h=10 > 1$

Therefore the graph of $y=cos(x)$ is:

Stretched vertically by a factor of 3.

Also as $h=10$ the graph is compressed horizontally by a factor $\frac{1}{10}$ .

Also, as $b =-\pi < 0$ The graph moves horizontally $\pi$ units to the rigth

6 0

2 years ago