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babunello [35]
1 year ago
5

Geometry questions....help me someone please

Mathematics
2 answers:
AlekseyPX1 year ago
8 0

Answer:

Triangle 1: x = 80 degrees, acute

Triangle 2: x = 10 degrees, right

Step-by-step explanation:

Triangle 1:

By the Sum of Interior Angles Theorem, all the angles inside the triangle adds up to 180 degrees. So, set up this equation:

60 + 40 +x = 180

Solve for x:

100 + x = 180\\x = 80

So, x = 80 degrees

Because all the angles are less than 90 degrees, this is an acute triangle.

Triangle 2:

By the Sum of Interior Angles Theorem, all the angles inside the triangle adds up to 180 degrees. So, set up this equation (with the right angle given):

3x + 60 + 90 = 180

Solve for x:

3x + 150 = 180\\3x = 30\\x = 10

So, x = 10 degrees

Because there is an angle measuring 90 degrees, this is a right triangle.

OLga [1]1 year ago
7 0

Answer:

Triangle 1: x = 80 degrees, acute

Triangle 2: x = 10 degrees, right

By the Sum of Interior Angles Theorem, all the angles inside the triangle adds up to 180 degrees. So, set up this equation:

Solve for x:

So, x = 80 degrees

Because all the angles are less than 90 degrees, this is an acute triangle.

Triangle 2:

By the Sum of Interior Angles Theorem, all the angles inside the triangle add up to 180 degrees. So, set up this equation (with the right angle given):

Solve for x:

So, x = 10 degrees

Because there is an angle measuring 90 degrees, this is a right triangle.

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eduard

Answer:

(27 y^(-8))/(4 x^6)

Step-by-step explanation:

Simplify the following:

(4 (3 x^2 y^4)^3)/(2 x^3 y^5)^4

Multiply each exponent in 2 x^3 y^5 by 4:

(4 (3 x^2 y^4)^3)/(2^4 x^(4×3) y^(4×5))

4×5 = 20:

(4 (3 x^2 y^4)^3)/(2^4 x^(4×3) y^20)

4×3 = 12:

(4 (3 x^2 y^4)^3)/(2^4 x^12 y^20)

2^4 = (2^2)^2:

(4 (3 x^2 y^4)^3)/((2^2)^2 x^12 y^20)

2^2 = 4:

(4 (3 x^2 y^4)^3)/(4^2 x^12 y^20)

4^2 = 16:

(4 (3 x^2 y^4)^3)/(16 x^12 y^20)

Multiply each exponent in 3 x^2 y^4 by 3:

(4×3^3 x^(3×2) y^(3×4))/(16 x^12 y^20)

3×4 = 12:

(4×3^3 x^(3×2) y^12)/(16 x^12 y^20)

3×2 = 6:

(4×3^3 x^6 y^12)/(16 x^12 y^20)

3^3 = 3×3^2:

(4×3×3^2 x^6 y^12)/(16 x^12 y^20)

3^2 = 9:

(4×3×9 x^6 y^12)/(16 x^12 y^20)

3×9 = 27:

(4×27 x^6 y^12)/(16 x^12 y^20)

4/16 = 4/(4×4) = 1/4:

(27 x^6 y^12)/(4 x^12 y^20)

Combine powers. (27 x^6 y^12)/(4 x^12 y^20) = (27 x^(6 - 12) y^(12 - 20))/4:

(27 x^(6 - 12) y^(12 - 20))/4

6 - 12 = -6:

(27 x^(-6) y^(12 - 20))/4

12 - 20 = -8:

Answer: (27 y^(-8))/(4 x^6)

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