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My name is Ann [436]
4 years ago
11

What kind of job is not at greater risk for workplace violence?

SAT
2 answers:
elena-14-01-66 [18.8K]4 years ago
6 0

Certain work factors, processes, and interactions can put people at increased risk from workplace violence. Examples include:

<span>Working with the public.Handling money, valuables or prescription drugs (e.g. cashiers, pharmacists).Carrying out inspection or enforcement duties (e.g. government employees).Providing service, care, advice or education (e.g. health care staff, teachers).Working with unstable or volatile persons (e.g. social services, or criminal justice system employees).Working in premises where alcohol is served (e.g. food and beverage staff).Working alone, in small numbers (e.g. store clerks, real estate agents), or in isolated or low traffic areas (e.g. washrooms, storage areas, utility rooms).Working in community-based settings (e.g. nurses, social workers and other home visitors).Having a mobile workplace (e.g. taxicab).Working during periods of intense organizational change (e.g. strikes, downsizing).</span>

Risk of violence may be greater at certain times of the day, night or year; For example,

<span>late hours of the night or early hours of the morningtax return seasonoverdue utility bill cut-off datesduring the holidayspay daysreport cards or parent interviewsperformance appraisals</span>

Risk of violence may increase depending on the geographic location of the workplace; for example,

<span>near buildings or businesses that are at risk of violent crime (e.g. bars, banks)<span>in areas isolated from other buildings or structures</span></span>
balu736 [363]4 years ago
4 0

Answer:

Job is not at greater risk for workplace violence is discussed below.

Explanation:

  • Operating with the citizens. Managing money, valuables or medicine prescriptions (e.g. treasurers, pharmacologists).
  • Taking out examination or implementation services (e.g. administration representatives). Rendering assistance, supervision, guidance or teaching (e.g. well-being care workers, teachers).

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Ed needed to extend the string on his kite. the current string was seven and three fourths feet. he cut a piece of string that m
Cloud [144]

The new length of the string is  (16 + 1/4) feet, then the correct option is the second one (counting from the top)

We know that the current string was (7 + 3/4) feet in length. Then they add another piece that measures 8.5 feet.

The new length of the string is given by the addition of the above two lengths, we will get:

L = (7 + 3/4) feet + 8.5 feet

We can rewrite the second length as a mixed number:

8.5 = 8 + 1/2 = 8 + 2/4

Replacing that we get:

L = (7 + 3/4) ft + 4.5 ft

 =  (7 + 3/4) ft + (8 + 2/4) ft

 = (7 + 8) ft + (3/4 + 2/4) ft

 = 15ft + 5/4ft = 15ft + (4/4 + 1/4)ft = (16 + 1/4)ft

The new length of the string is  (16 + 1/4) feet, then the correct option is the second one (counting from the top)

If you want to learn more about mixed numbers:

brainly.com/question/1746829

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3 0
2 years ago
A watch loses x minutes every y hours, at this rate how many hours will the watch lose in one week?
REY [17]
Minutes lost hourly is x/y.
One week has 24 * 7 = 168 hours.
168x / y would be minutes lost weekly, and (168/60) (x / y) = (42/15)(x/y) would be hours lost weekly.
7 0
3 years ago
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How many newtons of force are needed to accelerate a 1,875 kg object at a rate of 1. 5 m/s2?.
Inessa [10]

Answer:

2812.5 N

Explanation:

We know that

F = ma

F = 1875 × 1.5

F = 1875 × 15/10

F = 2812.5 N

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Suppose a certain scale is not calibrated correctly, and as a result, the mass of any object is displayed as 0. 75 kilogram less
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The correlation between the actual masses of a set of objects and the respective masses of the same set of objects displayed by the scale is; 1

<h3>What is the Correct Scale Calibration?</h3>

We are told that a certain scale is not calibrated correctly,

Mass displayed = 0.75 kg (less than its actual mass).

The scale of display = 1

Thus, the correlation between actual mass and displayed mass is 1 due to the fact that correlation is independent of change of origin and scale and correlation between any value and value minus 0.75 will be one.

Thus, the correlation between the actual masses of a set of objects and the respective masses of the same set of objects displayed by the scale is 1.

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