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Sonja [21]
3 years ago
11

What is equivelant to 5 to the power of -1?

Mathematics
1 answer:
Mazyrski [523]3 years ago
3 0
\frac{1}{5} Or  0.2
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1.In what ways did Egypt prosper during the reign of Hatshepsut? do your thing brainly!
Bond [772]

Answer:

She served as a queen, for Thutmose ll.

She served as queen alongside her husband, Thutmose II, but after his death, she claimed the role of pharaoh!. She reigned peace, she built temples and monuments, resulting in the flourishing of Egypt!

srry if this didn't help but I hope it did!

6 0
2 years ago
What is the expansion of (3+x)^4
Vlad1618 [11]

Answer:

\left(3+x\right)^4:\quad x^4+12x^3+54x^2+108x+81

Step-by-step explanation:

Considering the expression

\left(3+x\right)^4

Lets determine the expansion of the expression

\left(3+x\right)^4

\mathrm{Apply\:binomial\:theorem}:\quad \left(a+b\right)^n=\sum _{i=0}^n\binom{n}{i}a^{\left(n-i\right)}b^i

a=3,\:\:b=x

=\sum _{i=0}^4\binom{4}{i}\cdot \:3^{\left(4-i\right)}x^i

Expanding summation

\binom{n}{i}=\frac{n!}{i!\left(n-i\right)!}

i=0\quad :\quad \frac{4!}{0!\left(4-0\right)!}3^4x^0

i=1\quad :\quad \frac{4!}{1!\left(4-1\right)!}3^3x^1

i=2\quad :\quad \frac{4!}{2!\left(4-2\right)!}3^2x^2

i=3\quad :\quad \frac{4!}{3!\left(4-3\right)!}3^1x^3

i=4\quad :\quad \frac{4!}{4!\left(4-4\right)!}3^0x^4

=\frac{4!}{0!\left(4-0\right)!}\cdot \:3^4x^0+\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1+\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2+\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3+\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4

=\frac{4!}{0!\left(4-0\right)!}\cdot \:3^4x^0+\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1+\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2+\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3+\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4

as

\frac{4!}{0!\left(4-0\right)!}\cdot \:\:3^4x^0:\:\:\:\:\:\:81

\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1:\quad 108x

\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2:\quad 54x^2

\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3:\quad 12x^3

\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4:\quad x^4

so equation becomes

=81+108x+54x^2+12x^3+x^4

=x^4+12x^3+54x^2+108x+81

Therefore,

  • \left(3+x\right)^4:\quad x^4+12x^3+54x^2+108x+81
6 0
3 years ago
The difference between a number squared and 10 is 71 just translate please don't solve.
AnnyKZ [126]

Step-by-step explanation:

Things I notice about this problem:

  • "Difference" indicates subtraction.
  • "Is" means "equals".
  • When a problem simply says "a number," I replace it with a variable.

It is written out like this: x^{2} - 10 = 71.

3 0
3 years ago
2x+8y=5<br> 24x-4y=-15<br> the solution to the system is ( , ) ( , )
kicyunya [14]

[-½, ¾]; use either "Substitution" or "Elimination" to do this, and you'll see that this answer is correct.

3 0
3 years ago
A veteran treated 7 dogs this morning. The list gives the weights in pounds of each dog 41,36,20,36,62,5,6 find the range of the
serious [3.7K]

Answer:

57

Step-by-step explanation:

The range of a data set is

Largest data value - Smallest data value

62 - 5

= 57

The range of the data set is 57 pounds.

8 0
3 years ago
Read 2 more answers
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