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nalin [4]
2 years ago
14

Which equation is the equation of the line, in point-slope form, that has a slope of 2 and passes through the point (-8, 1)?

Mathematics
1 answer:
lutik1710 [3]2 years ago
5 0

Answer:

y=2x+17

Step-by-step explanation:

y-y1=m(x-x1)

y-1=2(x-(-8))

y-1=2(x+8)

y=2x+16+1

y=2x+17

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What's the area and perimeter of a right triangle with sides 5, 12 and 13( 5 and 12 are the base and height)
uysha [10]
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For positive acute angles A and B, it is known that tan A = 35/12 and sin B = 20/29. Find the value of sin(A - B ) in the simple
almond37 [142]

Answer:

\displaystyle \sin(A-B)=\frac{495}{1073}

Step-by-step explanation:

We are given that:

\displaystyle \tan(A)=\frac{35}{12}\text{ and } \sin(B)=\frac{20}{29}

Where both A and B are positive acute angles.

And we want to find he value of sin(A-B).

Using the first ratio, we can conclude that the opposite side is 35 and the adjacent side is 12.

Then by the Pythagorean Theorem, the hypotenuse is:

h = \sqrt{35^2 + 12^2} =37

Using the second ratio, we can likewise conclude that the opposite side is 20 and the hypotenuse is 29.

Then by the Pythagorean Theorem, the adjacent is:

a=\sqrt{29^2-20^2}=21

Therefore, we can conclude that:

So, for A, the adjacent is 12, opposite is 35, and the hypotenuse is 37.

For B, the adjacent is 21, opposite is 20, and the hypotenuse is 29.

We can rewrite sin(A-B) as:

\sin(A-B)=\sin(A)\cos(B)-\cos(A)\sin(B)

Using the above conclusions, this yields: (Note that since A and B are positive acute angles, all resulting ratios will be positive.)

\displaystyle \sin(A-B)=\Big(\frac{35}{37}\Big)\Big(\frac{21}{29}\Big)-\Big(\frac{12}{37}\Big)\Big(\frac{20}{29}\Big)

Evaluate:

\displaystyle \sin(A-B)=\frac{735-240}{1073}=\frac{495}{1073}

6 0
3 years ago
IMPORTANT PLEASE!! 10 POINTS :)
s344n2d4d5 [400]

Answer:

The domain is all the possible inputs for this function. The range is all the possible outputs for this function.

The line starts at the <em>x-value</em> of 0 and ends at the <em>x-value</em> of 12. Therefore, your domain is D: [0, 12].

The line starts at the <em>y-value</em> of 9000 and ends at the <em>y-value</em> of 0. Therefore, your range is R: [0, 9000].

5 0
3 years ago
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