<img src="https://tex.z-dn.net/?f=18x%20%2B%2020%20%2B%20x%20%3D%2010%28x%29%20-%203" id="TexFormula1" title="18x + 20 + x = 10(

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uysha [10]

3 years ago

x) - 3" alt="18x + 20 + x = 10(x) - 3" align="absmiddle" class="latex-formula">

Mathematics

2 answers:

-Dominant- [34]3 years ago

7 0

assuming you want us to solve for x

remember that you can do anything to an equation as long as you do it to both sides

18x+20+x=10x-3

combine like terms

19x+20=10x-3

minus 10x from both sides

19x-10x+20=10x-10x-3

9x+20=0-3

9x+20=-3

minus 20 from both sides

9x+20-20=-3-20

9x+0=-23

9x=-23

divide both sides by 9

$\frac{9x}{9}=\frac{-23}{9}$

$x(\frac{9}{9})=\frac{-23}{9}$

$x(1)=\frac{-23}{9}$

$x=\frac{-23}{9}$

Dima020 [189]3 years ago

4 0

18x + 20 + x = 10x -3

Combine like terms

19x + 20 = 10x -3

Subtract 20 to both sides because whatever you do on one side you have to do it on the other side:

19x = 10x -23

Subtract 10x

9x = -23

Divide 9 to isolate x:

x = -23/9

Simplify to get a mixed number:

x = -2 5/9

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Anni [7]

Given:

The matrix multiplication

$\begin{bmatrix}4&5&6\\1&2&3\end{bmatrix}\begin{bmatrix}10\\20\\30\end{bmatrix}$

To find:

The order of resulting matrix.

Solution:

We know that, if order of first matrix is $m_1\times n_1$ and the order of second matrix is $m_2\times n_2$ , then the order of these two matrices is $m_1\times n_2$ .

We have,

$\begin{bmatrix}4&5&6\\1&2&3\end{bmatrix}\begin{bmatrix}10\\20\\30\end{bmatrix}$

Here, the order of first matrix is $2\times 3$ and the order of the second matrix is $3\times 1$ . So, the order of the second matrix is $2\times 1$ . It is also written are 2 by 1.