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uysha [10]
3 years ago
8

x) - 3" alt="18x + 20 + x = 10(x) - 3" align="absmiddle" class="latex-formula">
Mathematics
2 answers:
-Dominant- [34]3 years ago
7 0

assuming you want us to solve for x

remember that you can do anything to an equation as long as you do it to both sides


18x+20+x=10x-3

combine like terms

19x+20=10x-3

minus 10x from both sides

19x-10x+20=10x-10x-3

9x+20=0-3

9x+20=-3

minus 20 from both sides

9x+20-20=-3-20

9x+0=-23

9x=-23

divide both sides by 9

\frac{9x}{9}=\frac{-23}{9}

x(\frac{9}{9})=\frac{-23}{9}

x(1)=\frac{-23}{9}

x=\frac{-23}{9}

Dima020 [189]3 years ago
4 0

18x + 20 + x = 10x -3

Combine like terms

19x + 20 = 10x -3

Subtract 20 to both sides because whatever you do on one side you have to do it on the other side:

19x = 10x -23

Subtract 10x

9x = -23

Divide 9 to isolate x:

x = -23/9

Simplify to get a mixed number:

x = -2 5/9

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+{-x2y+[-(x2y-2xy2+y2)+(-xy2-3y2+x2y)]-(10y2-x2y)}
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Answer:

3xy² -  14y²      

Step-by-step explanation:

I hope that this is the problem

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= - x²y + [ - x²y + 2xy² - y² + xy² - 3y² + x²y] - 10y² + x²y

Now combine like terms in the [  ].

= - x²y  + [ -x²y + x²y + 2xy² + xy² - y² - 3y² ] - 10y² + x²y

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=   (-x²y + x²y) + 3xy² + (-4y² - 10y²)

=       0 + 3xy² - 14y²

=  3xy² -  14y²       or    y²(3x - 14)

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