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gregori [183]
2 years ago
6

The x-intercept, or zero, of function g is x = . Function g is over the interval [-5, 5]. As the value of x approaches positive

infinity, the value of g(x) approaches infinity.
Mathematics
1 answer:
Aleksandr-060686 [28]2 years ago
7 0

Answer:

boom box second one one my bad just need points my g

Step-by-step explanation:

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A fabric manufacturer believes that the proportion of orders for raw material arriving late isp= 0.6. If a random sample of 10 o
ryzh [129]

Answer:

a) the probability of committing a type I error if the true proportion is p = 0.6 is 0.0548

b)

- the probability of committing a type II error for the alternative hypotheses p = 0.3 is 0.3504

- the probability of committing a type II error for the alternative hypotheses p = 0.4 is 0.6177

- the probability of committing a type II error for the alternative hypotheses p = 0.5 is 0.8281

Step-by-step explanation:

Given the data in the question;

proportion p = 0.6

sample size n = 10

binomial distribution

let x rep number of orders for raw materials arriving late in the sample.

(a) probability of committing a type I error if the true proportion is  p = 0.6;

∝ = P( type I error )

= P( reject null hypothesis when p = 0.6 )

= ³∑_{x=0 b( x, n, p )

= ³∑_{x=0 b( x, 10, 0.6 )

= ³∑_{x=0 \left[\begin{array}{ccc}10\\x\\\end{array}\right](0.6)^x( 1 - 0.6 )^{10-x

∝ = 0.0548

Therefore, the probability of committing a type I error if the true proportion is p = 0.6 is 0.0548

b)

the probability of committing a type II error for the alternative hypotheses p = 0.3

β = P( type II error )

= P( accept the null hypothesis when p = 0.3 )

= ¹⁰∑_{x=4 b( x, n, p )

= ¹⁰∑_{x=4 b( x, 10, 0.3 )

= ¹⁰∑_{x=4 \left[\begin{array}{ccc}10\\x\\\end{array}\right](0.3)^x( 1 - 0.3 )^{10-x

= 1 - ³∑_{x=0 \left[\begin{array}{ccc}10\\x\\\end{array}\right](0.3)^x( 1 - 0.3 )^{10-x

= 1 - 0.6496

= 0.3504

Therefore, the probability of committing a type II error for the alternative hypotheses p = 0.3 is 0.3504

the probability of committing a type II error for the alternative hypotheses p = 0.4

β = P( type II error )

= P( accept the null hypothesis when p = 0.4 )

= ¹⁰∑_{x=4 b( x, n, p )

= ¹⁰∑_{x=4 b( x, 10, 0.4 )

= ¹⁰∑_{x=4 \left[\begin{array}{ccc}10\\x\\\end{array}\right](0.4)^x( 1 - 0.4 )^{10-x

= 1 - ³∑_{x=0 \left[\begin{array}{ccc}10\\x\\\end{array}\right](0.4)^x( 1 - 0.4 )^{10-x

= 1 - 0.3823

= 0.6177

Therefore, the probability of committing a type II error for the alternative hypotheses p = 0.4 is 0.6177

the probability of committing a type II error for the alternative hypotheses p = 0.5

β = P( type II error )

= P( accept the null hypothesis when p = 0.5 )

= ¹⁰∑_{x=4 b( x, n, p )

= ¹⁰∑_{x=4 b( x, 10, 0.5 )

= ¹⁰∑_{x=4 \left[\begin{array}{ccc}10\\x\\\end{array}\right](0.5)^x( 1 - 0.5 )^{10-x

= 1 - ³∑_{x=0 \left[\begin{array}{ccc}10\\x\\\end{array}\right](0.5)^x( 1 - 0.5 )^{10-x

= 1 - 0.1719

= 0.8281

Therefore, the probability of committing a type II error for the alternative hypotheses p = 0.5 is 0.8281

3 0
2 years ago
I need to know this help
antoniya [11.8K]

Answer:

The slope is 2/3 and the y intercept is 5/9

Step-by-step explanation:

This is written in the form

y= mx+b where m is the slope and b is the y intercept

y = 2/3x +5/9

m = 2/3 and b=5/9

The slope is 2/3 and the y intercept is 5/9

4 0
3 years ago
I WILL MARK BRAINIEST<br> PLEASE HELP ASAP ITS DUE
Daniel [21]

Answer:

A) 1 : 4

B) 1 : 2

C) Base of M = 10 units

Step-by-step explanation:

A)

The ratio of the area of triangle M to triangle N

\frac {40}{160}= \frac{1}{4} = 1 : 4

B)

The ratio of the side lengths of triangle M to triangle N

\sqrt{ \frac {40}{160}} = \sqrt{\frac{1}{4}} \\\\={\frac{1}{2}} \\\\=1 : 2

C) Let the base of triangle M be b units.

\sqrt{ \frac {40}{160}} = \frac{b}{20}\\\\\frac{1}{2}=  \frac{b}{20}\\\\2b = 20\\\\b = \frac{20}{2} \\\\b = 10

8 0
2 years ago
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