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Mekhanik [1.2K]
4 years ago
15

Someone please help me

Mathematics
1 answer:
Tamiku [17]4 years ago
5 0

Answer: r= 5/2 or r= 2 1/2

Step-by-step explanation:

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Car travels 177 milies in 3 hours at a constant speed. Which unit ratio represents the speed of the car?
sp2606 [1]

Answer:

59 miles per hour

Step-by-step explanation:

6 0
3 years ago
A right triangle has a hypotenuse of length 21 and a leg of length 14. What is the length of the other leg of the triangle?
AlladinOne [14]
The answer is around 15.65.
6 0
3 years ago
A newspaper editor starts a retirement savings plan in which $225 per month is deposited at the beginning of each month into an
qwelly [4]

Answer: the value of this investment after 20 years is $112295.2

Step-by-step explanation:

We would apply the formula for determining future value involving deposits at constant intervals. It is expressed as

S = R[{(1 + r)^n - 1)}/r][1 + r]

Where

S represents the future value of the investment.

R represents the regular payments made(could be weekly, monthly)

r = represents interest rate/number of interval payments.

n represents the total number of payments made.

From the information given,

Since there are 12 months in a year, then

r = 0.066/12 = 0.0055

n = 12 × 20 = 240

R = $225

Therefore,

S = 225[{(1 + 0.0055)^240 - 1)}/0.0055][1 + 0.0055]

S = 225[{(1.0055)^240 - 1)}/0.0055][1.0055]

S = 225[{(3.73 - 1)}/0.0055][1.0055]

S = 225[{(2.73)}/0.0055][1.0055]

S = 225[496.36][1.0055]

S = $112295.2

7 0
4 years ago
Can you please answer the question?
Roman55 [17]

The <em>trigonometric</em> expression \frac{\tan^{2} \alpha}{\tan \alpha - 1} + \frac{\cot^{2} \alpha}{\cot \alpha - 1} is equivalent to the <em>trigonometric</em> expression \sec \alpha \cdot \csc \alpha + 1.

<h3>How to prove a trigonometric equivalence</h3>

In this problem we must prove that <em>one</em> side of the equality is equal to the expression of the <em>other</em> side, requiring the use of <em>algebraic</em> and <em>trigonometric</em> properties. Now we proceed to present the corresponding procedure:

\frac{\tan^{2} \alpha}{\tan \alpha - 1} + \frac{\cot^{2} \alpha}{\cot \alpha - 1}

\frac{\tan^{2}\alpha}{\tan \alpha - 1} + \frac{\frac{1}{\tan^{2}\alpha} }{\frac{1}{\tan \alpha} - 1 }

\frac{\tan^{2}\alpha}{\tan \alpha - 1} - \frac{\frac{1 }{\tan \alpha} }{\tan \alpha - 1}

\frac{\frac{\tan^{3}\alpha - 1}{\tan \alpha} }{\tan \alpha - 1}

\frac{\tan^{3}\alpha - 1}{\tan \alpha \cdot (\tan \alpha - 1)}

\frac{(\tan \alpha - 1)\cdot (\tan^{2} \alpha + \tan \alpha + 1)}{\tan \alpha\cdot (\tan \alpha - 1)}

\frac{\tan^{2}\alpha + \tan \alpha + 1}{\tan \alpha}

\tan \alpha + 1 + \cot \alpha

\frac{\sin \alpha}{\cos \alpha} + \frac{\cos \alpha}{\sin \alpha} + 1

\frac{\sin^{2}\alpha + \cos^{2}\alpha}{\cos \alpha \cdot \sin \alpha} + 1

\frac{1}{\cos \alpha \cdot \sin \alpha} + 1

\sec \alpha \cdot \csc \alpha + 1

The <em>trigonometric</em> expression \frac{\tan^{2} \alpha}{\tan \alpha - 1} + \frac{\cot^{2} \alpha}{\cot \alpha - 1} is equivalent to the <em>trigonometric</em> expression \sec \alpha \cdot \csc \alpha + 1.

To learn more on trigonometric expressions: brainly.com/question/10083069

#SPJ1

6 0
2 years ago
Circle D circumscribes ABC and ABE. Which statements about the triangles are true? Statement I: The perpendicular bisectors of A
mestny [16]

Answer:

The correct option is;

B. I and II

Step-by-step explanation:

Statement I: The perpendicular bisectors of ABC intersect at the same point as those of ABE

The above statement is correct because given that ΔABC and ΔABE are inscribed in the circle with center D, their sides are equivalent or similar to tangent lines shifted closer to the circle center such that the perpendicular bisectors of the sides of ΔABC and ΔABE are on the same path as a line joining tangents to the center pf the circle

Which the indicates that the perpendicular the bisectors of the sides of ΔABC and ΔABE will pass through the same point which is the circle center D

Statement II: The distance from C to D is the same as the distance from D to E

The above statement is correct because, D is the center of the circumscribing circle and D and E are points on the circumference such that distance C to D and D to E are both equal to the radial length

Therefore;

The distance from C to D = The distance from D to E = The length of the radius of the circle with center D

Statement III: Bisects CDE

The above statement may be requiring more information

Statement IV The angle bisectors of ABC intersect at the same point as those of ABE

The above statement is incorrect because, the point of intersection of the angle bisectors of ΔABC and ΔABE are the respective in-centers found within the perimeter of ΔABC and ΔABE respectively and are therefore different points.

6 0
3 years ago
Read 2 more answers
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