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goblinko [34]
3 years ago
10

When you go swimming the pressure in your ears varies directly with the depth at which you swim. At 10 feet, the pressure is abo

ut 4.3 pounds per square inch (psi). a) Write the variation function. b) Predict the pressure at 50 feet. c) It is unsafe for amateur divers to swim where the pressure is more than 65 psi. How deep can an amateur swimmer safely swim (round to the nearest thousandth)
Mathematics
1 answer:
Serjik [45]3 years ago
8 0

Answer:

(a) p = 0.43d

(b) p = 21.5

(c) d = 151.163

Step-by-step explanation:

Given

Variation: Direct

Represent ear pressure with p and depth with d.

So, we have:

p\ \alpha\ d

d =10 when p =4.3

Solving (a): Write a variation

We have:

p\ \alpha\ d

Write as an equation

p = kd

Where: k is the constant of variation

d =10 when p =4.3

So, we have:

4.3 = k * 10

Make k the subject

k = \frac{4.3}{10}

k = 0.43

Substitute 0.43 for k in p = kd

p = 0.43d

Solving (b): Pressure at 50 feet

Substitute 50 for d in p = 0.43d

p = 0.43 * 50

p = 21.5

The pressure is 21.5 pounds per square

Solving (c): The safe depth

The safe depth stops at a pressure of 65psi.

Substitute 65 for p in p = 0.43d

65 = 0.43 * d

Make d the subject

d = \frac{65}{0.43}

d = 151.162790698

d = 151.163 -- approximated

<em>The safe distance for an amateur is 151.163ft</em>

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