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oksian1 [2.3K]
2 years ago
8

your friend says that the absolute value equation | 3x + 8 |-9= -5 has no solution because the constant on the right side of the

equation is negative. is your friend correct ? explain.
Mathematics
1 answer:
Simora [160]2 years ago
7 0

Hello from MrBillDoesMath!

Answer:

Your friend is incorrect


Discussion:

| 3x + 8 | -9  = -5           =>    ( add 9 to both sides)

| 3x + 8 |  -9 + 9 = -5 + 9 =>

| 3x + 8 |  = 4 =>

3x +8 = 4  or  3x + 8 = -4 =>

x = -4/3    or   x = -4



Thank you,

MrB


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Putting your given numbers into the formula, we have

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3 years ago
A rectangle has its vertices at (-4, -3), (-4,7), (1,7), (1, -3). What part, in percent, of the rectangle is located in Quadrant
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Consider the attached figure. The whole rectangle is ABCD, while AEGF is the part located in the third quadrant. In fact, this quadrant is composed by all the points with both coordinates negative.

To answer the question, let's compute the area of the two rectangles and see what part of ABCD is AEGF.

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3 0
3 years ago
Help me I need help I need help
Licemer1 [7]

Answer:

\Huge\boxed{131.88}

Step-by-step explanation:

Hello There!

First thing we want to do is find the formula for circumference of a circle

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where r = radius

we are given the diameter so we have to convert that into radius to do so we just divide by 2

42/2=21 so the radius equals 21 inches

now we just plug in 21 for r in the formula

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12<br> Using side lengths only, could the triangles be similar?<br> 0.5<br> m05 1 1.5
Murljashka [212]

Answer:

\large\boxed{\text{No.}\ \dfrac{0.5}{1}\neq\dfrac{1}{1.5}\neq\dfrac{1.5}{2}}

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\text{Let}\\ a,\ b,\ c\ -\ \text{sides of a triangle ABC, where}\ a\leq b\leq c\\d,\ e,\ f\ -\ \text{sides of a triangle}\ DE F,\ \text{where}\ d\leq e\leq f.\\\\\triangle ABC\sim\triangle DE F\iff\dfrac{a}{d}=\dfrac{b}{e}=\dfrac{c}{f}\\\\/\text{corresponding sides are in proportion}/

\bold{WARNING !!!}\\\\\text{No triangle like QRS exists!}\\\\1 + 0.5 = 1.5 !!!\\\\\text{The sum of the lengths of the two shorter sides of the triangle}\\\text{must be greater than the length of the longest side.}

\text{Despite this, let's check the ratios}

\text{We have:}\\\\\triangle XYZ\to a=1,\ b=1.5,\ c=2\\\triangle QRS\to d=0.5,\ e=1,\ f=1.5

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