What is the lowest common denominator of the following two fractions? 1/4 and 1/6

Please help! Brainliest Answer! Thank You!

ziro4ka [17]

Answer:

B) 63°

Step-by-step explanation:

Step 1: find the angle beside x (inside the pentagon)

*A pentagon has a total of 540°

119 + 100 + 116 + 88 = 423

540 - 423 = 117

Step 2: x is a supplementary angle, which means it's angle adds up to 180°

Since we know the other angle is 117°, we just subtract that from 180

180 - 117 = 63

x = 63

5 0

3 years ago

Solve using Fourier series.

Olin [163]

With $2L=\pi$ , the Fourier series expansion of $f(x)$ is

$\displaystyle f(x)\sim\frac{a_0}2+\sum_{n\ge1}a_n\cos\dfrac{n\pi x}L+\sum_{n\ge1}b_n\sin\dfrac{n\pi x}L$
$\displaystyle f(x)\sim\frac{a_0}2+\sum_{n\ge1}a_n\cos2nx+\sum_{n\ge1}b_n\sin2nx$

where the coefficients are obtained by computing

$\displaystyle a_0=\frac1L\int_0^{2L}f(x)\,\mathrm dx$
$\displaystyle a_0=\frac2\pi\int_0^\pi f(x)\,\mathrm dx$

$\displaystyle a_n=\frac1L\int_0^{2L}f(x)\cos\dfrac{n\pi x}L\,\mathrm dx$
$\displaystyle a_n=\frac2\pi\int_0^\pi f(x)\cos2nx\,\mathrm dx$

$\displaystyle b_n=\frac1L\int_0^{2L}f(x)\sin\dfrac{n\pi x}L\,\mathrm dx$
$\displaystyle b_n=\frac2\pi\int_0^\pi f(x)\sin2nx\,\mathrm dx$

You should end up with

$a_0=0$
$a_n=0$
(both due to the fact that $f(x)$ is odd)
$b_n=\dfrac1{3n}\left(2-\cos\dfrac{2n\pi}3-\cos\dfrac{4n\pi}3\right)$

Now the problem is that this expansion does not match the given one. As a matter of fact, since $f(x)$ is odd, there is no cosine series. So I'm starting to think this question is missing some initial details.

One possibility is that you're actually supposed to use the even extension of $f(x)$ , which is to say we're actually considering the function

$\varphi(x)=\begin{cases}\frac\pi3&\text{for }|x|\le\frac\pi3\\0&\text{for }\frac\pi3$

and enforcing a period of $2L=2\pi$ . Now, you should find that

$\varphi(x)\sim\dfrac2{\sqrt3}\left(\cos x-\dfrac{\cos5x}5+\dfrac{\cos7x}7-\dfrac{\cos11x}{11}+\cdots\right)$

The value of the sum can then be verified by choosing $x=0$ , which gives

$\varphi(0)=\dfrac\pi3=\dfrac2{\sqrt3}\left(1-\dfrac15+\dfrac17-\dfrac1{11}+\cdots\right)$
$\implies\dfrac\pi{2\sqrt3}=1-\dfrac15+\dfrac17-\dfrac1{11}+\cdots$

as required.

5 0

3 years ago

Ind the next term for the given sequence.52, 45, 38, 31,

o-na [289]

The answer is 24. To get from one term to the next, you have to find the difference. To get from 52 to 45, you minus 7. It is the same with the other terms. So 31 - 7 = 24

4 0

3 years ago

Read 2 more answers

Please help me I <img src="https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20%20-%20%20%7By%7D%5E%7B2%7D%20%20%2B%204y%20-%204"

Ivenika [448]

Answer:

${x}^{2} - {y}^{2} + 4y - 4 \\ \\ {x}^{2} - ( {y}^{2} .2.y.y + {2}^{2} ) \\ \\ {x}^{2} - (y - 2) {}^{2} \\ \\ (x + y - 2)(x - y + 2)$

4 0

3 years ago

Read 2 more answers

Y=-2/3x+3 please show the work thank you ;)

Ivahew [28]

Answer:

Step-by-step explanation:

Looking at y=-%282%2F3%29x%2B3 we can see that the equation is in slope-intercept form y=mx%2Bb where the slope is m=-2%2F3 and the y-intercept is b=3

Since b=3 this tells us that the y-intercept is .Remember the y-intercept is the point where the graph intersects with the y-axis

So we have one point

Now since the slope is comprised of the "rise" over the "run" this means

slope=rise%2Frun

Also, because the slope is -2%2F3, this means:

rise%2Frun=-2%2F3

which shows us that the rise is -2 and the run is 3. This means that to go from point to point, we can go down 2 and over 3

So starting at , go down 2 units

and to the right 3 units to get to the next point

Now draw a line through these points to graph y=-%282%2F3%29x%2B3

So this is the graph of y=-%282%2F3%29x%2B3 through the points and

3 0

3 years ago