<h3>
Answer:</h3>
5 Adults; 6 Children
<h3>
Step-by-step explanation:</h3>
If all the tickets purchased were child tickets, the cost would be 11×$35.95 = $384.45. The actual cost is $434.45 -384.45 = $50 more than that.
Changing a child's admission to an adult's admission adds $10 to the cost, so there must have been $50/$10 = 5 adult admissions in the mix. Of course, 11 - 5 = 6, the number of child admissions.
The families bought 5 adult tickets and 6 child tickets.
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<em>Using an equation</em>
Let x represent the number of adult admissions. Then 11-x is the number of child admissions, and the total cost is ...
... 44.95x + 34.95(11 -x) = 434.45
... 10x = 50 . . . . . . . . subtract 384.45 and simplify (compare to the above)
... 50/10 = x = 5 . . . . the number of adult admissions
the assumption being, that the angles at vertices C and B are right-angles, namely 90°, which will mean that C and B are points of tangency, since tangent lines and radius segments always meet at right-angles.
well, the tangents lines meet outside at a certain point, here at vertex A, when that happens, both outside tangents are the same length, so AB = 6 = AC.
If the inscribed square has sides of 8in, the diameter of the circle is equal to the diagonal of the square.
d^2=x^2+x^2
d^2=2x^2
d=√(2x^2)
Since d=2r, r=d/2 so
r=(1/2)√(2x^2)
r=√((2x^2)/4)
r=√(x^2/2), since x=8
r=√(64/2)
r=√32
r=√(16*2)
r=4√2 in (exact)
r≈5.66 in (to nearest hundredth of an inch)
It is on sale for 50 percent so 320 is = 50 percent
100 percent = 640
Answer:
x > -6 is the answer I think