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elena-14-01-66 [18.8K]
3 years ago
8

The side of a square is x, and the area is A. Express A in terms of x. Draw the graph which shows how A depends on x.

Mathematics
1 answer:
Alexandra [31]3 years ago
4 0

a=x squared or x times itself

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8n=7n + 1/2<br>please help me
natka813 [3]
I hope this helps you




8n=7n+1/2



2.8n=7n+1



16n-7n =1



9n=1



n=1/9


7 0
3 years ago
Read 2 more answers
Which statement describes the system of equations?
Masja [62]

Answer:

1.) It has one solution (–5, 5).

if you click on the photo it will show you how to get the answer. I hope this helps you.

7 0
2 years ago
What is the x-intercept of the graph -4x=20
nataly862011 [7]

Answer:

-4x=20

x=20/-4

x=-5

maybe not sure

5 0
3 years ago
A professor gives two types of quizzes, objective and recall. He is planning to give at least 15
nadya68 [22]

Answer:

x₁ = 20     x₂ = 0

z (min) = 20

Step-by-step explanation:

According to the problem statement:

Let´s call

Objective quiz =  x₁               Recall quiz =  x₂

First constraint

Quantity of quizzes at least 15

x₁  +  x₂  ≥ 15

Second constraint:

Preparation time   at least 300 minutes, then

15*x₁  +  30*x₂  ≥   300

Third constraint

Average score  at least  85 points

7*x₁  +  5*x₂   ≥  85

General constraint x₁ ≥ 0   x₂ ≥ 0

Objective function z is:

z = 1* x₁ + 1,5*x₂     to minimize

The model:

z = x₁  + 1,5x₂      to minimize

Subject to

x₁  +  x₂  ≥ 15

15*x₁  +  30*x₂  ≥   300

7*x₁  +  5*x₂   ≥  85

Using Atozmax (online solver) we find

x₁ = 20     x₂ = 0

z (min) = 20

5 0
2 years ago
Emily is training for a 10K race. On day one, she runs for 20 minutes. On day two, she runs for 30 minutes. On day three, she ru
Rina8888 [55]

Answer:

90 minutes

Step-by-step explanation:

Given that On day one, she runs for 20 minutes. On day two, she runs for 30 minutes. On day three, she runs for 40 minutes, this pattern may be presented as an arithmetic sequence shown below

20, 30, 40 ...

For an arithmetic sequence whose first term is a, and a common difference d, the nth term of the sequence may be given as

Tn = a + (n - 1)d

Hence the first term is 20, the common difference d is 10

On the 8th day, the 8th term

T8 = 20 + (8 - 1) 10

= 20 + 70

= 90 minutes

8 0
3 years ago
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