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2 years ago

Please help me answer this question.

Mathematics

2 answers:

Wittaler [7]2 years ago

7 0

Answer:

I might be wrong though

Fiesta28 [93]2 years ago

4 0

Answer:

The numbers are 21, 5, 5, 5.

21+5+5+5=36

21*5*5*5=2625

Step-by-step explanation:

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Hello can you please help me posted picture of question

zhuklara [117]

Since the order of selection does not matter, we will use combinations to solve this problem.

We are to form the combination of 30 objects taken 6 at a time. This can be expressed as 30C6.

$30C6= \frac{30!}{6!*24!} \\ \\ 
= 593775$

This means the six teachers can be selected in 593775 ways.

So the correct answer is option A

3 0

3 years ago

a lamp post cast a Shadow 15 feet long while a 6 foot man standing nearby cast a shadow 5 ft long. what proportion can be used t

kolezko [41]

Answer:

6/5=x/15

Step-by-step explanation:

6/5=x/15,where x is hight of the lamp post

x=18

3 0

3 years ago

Marcus buys a tent priced at $50 if the sales tax is 5% how much tax will Marcus pay

seraphim [82]

5% = 0.05

50 x 0.05 = $2.50

Total tax will be $2.50

Total amount he will pay = 50 + 2.50 = $52.50

3 0

3 years ago

Read 2 more answers

#54 Simplify and write the answers using positive exponents only.

kramer

Gg easy

remember
(x^m)/(x^n)=x^(m-n)
and
(x^m)^n=x^(mn)
and
(xyz)^m=(x^m)(y^m)(z^m)
and
(m/n)^a=(m^a)/(n^a)
and
x^-n=1/(x^n)

so
$( \frac{6mn^{-2}}{3m^{-1}n^2} )^{-3}$ =
$( \frac{6}{3} )^{-3}( \frac{m}{m^{-1}} )^{-3}( \frac{n^{-2}}{n^2} )^{-3}$ =
$(2^{-3})((m^2)^{-3})((n^{-4})^{-3})$ =
$( \frac{1}{2^3})(m^{-6})(n^{12})$ =
$( \frac{1}{8} )( \frac{1}{m^6})(n^{12})$ =
$\frac{n^{12}}{8m^6}$

8 0

3 years ago

Which of the following functions has the largest value when x= 3? Show your work.

luda_lava [24]

Answer:

p(x)

Step-by-step explanation:

Substitute x = 3 into each function and calculate the value.

p(3) = 2(3)² + 4(3) + 11 = 2(9) + 12 + 11 = 18 + 12 + 11 = 41

h(3) = 4(3) = 12

s(3) = 10(3) = 30

Thus p(x) = 41 is the largest value when x = 3

6 0

3 years ago