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labwork [276]
3 years ago
8

A square pyramid is shown below: What is the surface area of the pyramid?

Mathematics
1 answer:
Reptile [31]3 years ago
8 0
Well first you would find the area of the square on the bottom
Which would be:
            0.7*0.7= .49
Then we would find the area of one of the triangles on the side:
           8*0.7= 5.6* 1/2= 2.8
Next, you will multiply the 2.8 by 4, because there are 4 triangles:
          2.8*4=11.2
Finally add the 11.2 to the area of the square, and you'll have your answer.
          .49+11.2= 11.69
So, B is your answer

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Liono4ka [1.6K]

Answer:

The Last One

Step-by-step explanation:

8y = 5 - 4x

y = 5/8 - (1/2)x

5 0
2 years ago
263.000 divided by 7
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Answer:

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Step-by-step explanation:

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4 0
2 years ago
Find equations of the tangent plane and the normal line to the given surface at the specified point. x + y + z = 8exyz, (0, 0, 8
Dima020 [189]

Let f(x,y,z)=x+y+z-8e^{xyz}. The tangent plane to the surface at (0, 0, 8) is

\nabla f(0,0,8)\cdot(x,y,z-8)=0

The gradient is

\nabla f(x,y,z)=\left(1-8yze^{xyz},1-8xze^{xyz},1-8xye^{xyz}\right)

so the tangent plane's equation is

(1,1,1)\cdot(x,y,z-8)=0\implies x+y+(z-8)=0\implies x+y+z=8

The normal vector to the plane at (0, 0, 8) is the same as the gradient of the surface at this point, (1, 1, 1). We can get all points along the line containing this vector by scaling the vector by t, then ensure it passes through (0, 0, 8) by translating the line so that it does. Then the line has parametric equation

(1,1,1)t+(0,0,8)=(t,t,t+8)

or x(t)=t, y(t)=t, and z(t)=t+8.

(See the attached plot; the given surface is orange, (0, 0, 8) is the black point, the tangent plane is blue, and the red line is the normal at this point)

4 0
3 years ago
a bus is traveling at a constant speed.if the bus is 15 1/2 miles in 1/3 of an hour. how many miles will the bus travel in one h
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A

Step-by-step explanation:

A

3 0
2 years ago
Read 2 more answers
Using suitable identity find 231^222-131^2​
Sliva [168]

Given:

Consider the expression is

231^2-131^2

To find:

The value of given expression using a suitable identity.

Solution:

We have,

231^2-131^2

Using the identity a^2-b^2=(a-b)(a+b), we get

231^2-131^2=(231-131)(231+131)

231^2-131^2=(100)(362)

231^2-131^2=36200

Therefore, the value of the given expression is 231^2-131^2=36200.

7 0
2 years ago
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