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labwork [276]
3 years ago
8

A square pyramid is shown below: What is the surface area of the pyramid?

Mathematics
1 answer:
Reptile [31]3 years ago
8 0
Well first you would find the area of the square on the bottom
Which would be:
            0.7*0.7= .49
Then we would find the area of one of the triangles on the side:
           8*0.7= 5.6* 1/2= 2.8
Next, you will multiply the 2.8 by 4, because there are 4 triangles:
          2.8*4=11.2
Finally add the 11.2 to the area of the square, and you'll have your answer.
          .49+11.2= 11.69
So, B is your answer

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taurus [48]

Answer:

y(t) = c₁ e^(-1/2 t) cos(√3/2 t) + c₂ e^(-1/2 t) sin(√3/2 t) + 1

Step-by-step explanation:

y" + y' + y = 1

This is a second order nonhomogenous differential equation with constant coefficients.

First, find the roots of the complementary solution.

y" + y' + y = 0

r² + r + 1 = 0

r = [ -1 ± √(1² − 4(1)(1)) ] / 2(1)

r = [ -1 ± √(1 − 4) ] / 2

r = -1/2 ± i√3/2

These roots are complex, so the complementary solution is:

y = c₁ e^(-1/2 t) cos(√3/2 t) + c₂ e^(-1/2 t) sin(√3/2 t)

Next, assume the particular solution has the form of the right hand side of the differential equation.  In this case, a constant.

y = c

Plug this into the differential equation and use undetermined coefficients to solve:

y" + y' + y = 1

0 + 0 + c = 1

c = 1

So the total solution is:

y(t) = c₁ e^(-1/2 t) cos(√3/2 t) + c₂ e^(-1/2 t) sin(√3/2 t) + 1

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